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arlik [135]
3 years ago
11

Never mind no one will answer it

Mathematics
2 answers:
olga nikolaevna [1]3 years ago
7 0

Answer:

sorry that no one answered your question

Step-by-step explanation:

Vinil7 [7]3 years ago
5 0
What
ask the question I will answer it
go ahead ask
You might be interested in
If 10 mm = 1 cm, how many millimeters are in 22 centimeters?<br><br> Group of answer choices
san4es73 [151]

Answer:

220 millimeters

Step-by-step explanation:

If you take 22 cm * 10mm/1cm you get 220 mm

Please rate!

6 0
2 years ago
Solve for x .<br>-2z-xy=z+7
vovangra [49]

-2z - xy = z + 7

You are solving for x. Note the equal sign. What you do to one side, you do to the other. Isolate the x.

First, add 2z to both sides

-2z (+2z) - xy = z + 7 (+2z)

Simplify. Combine like terms

-xy = z + 2z + 7

-xy = 3z + 7

Completely isolate the x. Divide -y from both sides

(-xy)/-y = (3z + 7)/-y

x = (3z + 7)/-y

Simplify

z = (3z + 7)/(-y) is your answer

hope this helps

7 0
3 years ago
Read 2 more answers
Find the intervals on which​ f(x) is​ increasing, the intervals on which​ f(x) is​ decreasing, and the local extrema. f (x )equa
Kaylis [27]

Answer:

f(x) is increasing in the intervals (-∞,-4) and (9,∞)

f(x) is decreasing in the ingercal (-4,9)

The local extrema is:

local max at (-4,496)

and local min at (9,-1701)

Step-by-step explanation:

In order to solve this problem we must start by finding the derivative of the provided function, which we can find by using the power rule.

if f(x)=ax^{n} then f'(x)=anx^{n-1}

so we get:

f(x)=2x^{3}-15x^{2}-216x

f'(x)=6x^{2}-30x-216

in order to find the critical points we mus set the derivative equal to zero, since the local max an min will happen when the slope of the tangent line to the given point is zero, so we get:

6x^{2}-30x-216=0

we can solve this by factoring, so let's factor that equation:

6(x+4)(x-9)=0

we can now set each of the factors equal to zero so we get:

x+4=0 and x-9=0

when solving each for x we get that:

x=-4 and x=9

These are our critical points, now we can build the possible intervals we are going to use to determine where the function will be increasing and where it will be decreasing:

(-∞,-4), (-4,9) and (9,∞)

so now we need to test these intervals in the derivative to see if the graph will be increasing or decreasing in the given intervals. So let's pick x=-5 for the first one, x=0 for the second one and x=10 for the third one.

When evaluating them into the first derivative we get that:

f'(-5)=84, this is a positive answer so it means that the function is increasing in the interval (-∞,--4)

f'(0)=-216, this is a negative anser so it means that the function is decreasing in the interval (-4,9)

f'(10)=84, this is a positive answer so it means that the function is increasing in the interval (9,∞)

Now, for the local extrema, we can see that at x=-4, the function it's increasing on the left of this point while it's decreasing to the right, which means that there will be a local maximum at x=-4, so the local max is the point (-4,496)

We can see that at x=9, the function it's decreasing on the left of this point while it's increasing to the right, which means that there will be a local minimum at x=-9, so the local min is the point (9,-1701)

7 0
3 years ago
Why is it important to use a device like a random number table in a simulation?
Jet001 [13]
I don’t think it’s the second or third one I’m narrowing it down to the first or maybe fourth

I think the answer is the first one though
5 0
3 years ago
i need to find the zeros by factoring but im stuck plss help me i think the zeros may be 0, 1, -4, and 4 but i dont know how to
Sveta_85 [38]
This should help you on how to get the zeros and the answer for the bottom question is A

5 0
2 years ago
Read 2 more answers
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