With continuous data, it is possible to find the midpoint of any two distinct values. For instance, if h = height of tree, then its possible to find the middle height of h = 10 and h = 7 (which in this case is h = 8.5)
On the other hand, discrete data can't be treated the same way (eg: if n = number of people, then there is no midpoint between n = 3 and n = 4).
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With that in mind, we have the following answers
1) Continuous data. Time values are always continuous. Any two distinct time values can be averaged to find the midpoint
2) Continuous data. Like time values, temperatures can be averaged as well.
3) Discrete data. Place locations in a race or competition are finite and we can't have midpoints. We can't have a midpoint between 9th and 10th place for instance.
4) Continuous data. We can find the midpoint and it makes sense to do so when it comes to speeds.
5) Discrete data. This is a finite number and countable. We cannot have 20.5 freshman for instance.
Answer:
thx
Step-by-step explanation:
Answer: Annie has 49 Quarters
Explanation:
Sarah has 21 more quarters than Annie.
As shown, It says That Sarah has 28 quarters.
So, if Sarah has 21 more, it means you add 21 + 28
Resulting in 49.
Hope this helps you! If available please give me a Branliest. It is much appreciated!
- Mathhotdog •~•
Answer: FALSE
<u>Step-by-step explanation:</u>
x⁵ + 0x⁴ - 4x³ + 2x² - 4x + 1
If x - 2 is a factor, then x =2 should result in a remainder of 0 when using synthetic division.
2 | 1 0 -4 2 -4 1
<u>| ↓ 2 4 0 4 0 </u>
1 2 0 2 0 1 ← Remainder ≠ 0 so x - 2 is NOT a factor
