Okay so what you would is press ctrl+alt+delete and click log out i think but if you have a disk put it in and secure everything trust me i am a computer savage. i hack thing all the time.
I believe the answer is C.
Answer:
"The value of the variable will remain the same which is already have when the sub-processor is called".
Explanation:
The above question said that:-
void fun(int a)
{
a=a+1;
}
void main()
{
int a=5;
fun(a);
}
//what will be the value of a in the main function after the fun function is excuted.
- Then the answer is: the value of a will be 5 in the main function.
- It is because when the fun function is called, then a variable that is defined in the fun function is a local variable for fun function. That scope after the fun function is null.
- The a variable inside the fun function is a different variable and the main function a variable is also a different variable.
- So when the user prints the value of a variable inside the fun function, it will give the result as 6.
- But when he prints the value of a variable inside the main function, then it will give the value as 5.
