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nikdorinn [45]
2 years ago
14

"Technician A says that Ohm's law can be used to determine circuit current flow if total circuit resistance and total voltage ar

e known. Technician B says that Ohm's law can be used to calculate the unknown resistance of a load in a circuit if total current and source voltage are known. Which technician is correct?
Computers and Technology
1 answer:
Troyanec [42]2 years ago
6 0

Answer:

Both Technicians are correct.

Explanation:

Remember that Ohm's Law its a relationship between Voltage (E), Current (I) and Resistance (R) in an electrical circuit. This relationship is defined by the following equation:

E=I*R

Each one of the letters could be called a variable. Now, also remember that the number of equations you have is equal to the number of variables unknown you could have.

In Ohm's Law you have 3 variables (E,I,R) and 1 equation. It means that you need to know 2 variables (Whatever 2 variables) to know the third.

Technician A says, in other words, that could calculate the Circuit current flow (I) knowing total circuit resistance (R) and total voltage (E). Note that Technician A knows 2 to 3 variables, then it's possible to use Ohm's Law with the following equation:

I=\frac{E}{R}

Technician B says, in other words, that could determine the unknown resistance (R) knowing total current (I) and source voltage (E). Once again, note that Technician B knows 2 to 3 variables, then it's possible to use Ohm's Law with the following equation:

R=\frac{E}{I}

It is concluded that both technicians are right.

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The sum of all the minterms of a boolean function of n variables is equal to 1.
Aleksandr-060686 [28]

The answers are as follows:

a) F(A, B, C) = A'B'C' + A'B'C + A'BC' + A'BC + AB'C' + AB'C + ABC' + ABC

= A'(B'C' + B'C + BC' + BC) + A((B'C' + B'C + BC' + BC)

= (A' + A)(B'C' + B'C + BC' + BC) = B'C' + B'C + BC' + BC

= B'(C' + C) + B(C' + C) = B' + B = 1


b) F(x1, x2, x3, ..., xn) = ∑mi has 2n/2 minterms with x1 and 2n/2 minterms

with x'1, which can be factored and removed as in (a). The remaining 2n1

product terms will have 2n-1/2 minterms with x2 and 2n-1/2 minterms

with x'2, which and be factored to remove x2 and x'2, continue this

process until the last term is left and xn + x'n = 1

4 0
3 years ago
Assume that a variable variable, number Of Sides has been initialized. Write a statement that assigns the value True to the vari
inna [77]

Answer:

public class ANot {

   public static void main(String[] args) {

   

       int numberOfSides = 20;

       boolean isQuadrilateral;

       if(numberOfSides==4){

           isQuadrilateral = true;

           System.out.println("The triangle is quadrilateral");

       }

       else{

           isQuadrilateral=false;

           System.out.println("The triangle is not quadrilateral");

       }          

}

}

Explanation:

  1. Create and Initilize the int  variable numberOfSides (You can also receive this from a user using the scanner class for example).
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  3. Use if and else statement to check if numberOfSides ==4 and assign true to isQuadrilateral else assign false
7 0
3 years ago
Create a conditional expression that evaluates to string "negative" if userVal is less than 0, and "non-negative" otherwise. Ex:
ArbitrLikvidat [17]

Answer:

import java.util.Scanner;

public class Main

{

public static void main(String[] args) {

 Scanner input = new Scanner(System.in);

 

 System.out.print("Enter a number: ");

 int userVal = input.nextInt();

 

 String aString;

 if(userVal < 0)

     aString = "negative";

 else

     aString = "non-negative";

     

 System.out.println(aString);

}

}

Explanation:

Ask the user to enter a number and set it to userVal

Check the value of userVal. If it is smaller than 0, set the string as "negative". If it is not, set it as "non-negative"

Print the string

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3 0
3 years ago
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Vanyuwa [196]

Answer:

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Explanation:

7 0
3 years ago
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