Let's find the derivative of that hyperbola in order to find a slope formula to help us with this equation. We already have an x and y value. The derivative is found this way: 
so 
. The derivative supplies us with the slope formula we need to write the equation. Sub in the x value of 3 to find what the slope is: 
. So in our slope-intercept equation, x = 3, y = 1, and m = -1/3. Use these values to solve for b. 
so b = 2. The equation, then, for the line tangent to that hyperbola at that given point is 
What is 2/3+485-47/34+578/2-3456+16?
2 answers:
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Answer:
A choice
Step-by-step explanation:
sec is defined as 1/cos.
cos is again defined as adjacent to hypotenuse.
We know that adjacent is x and hypotenuse is r.
Therefore:- cos is x/r
Now sec is 1/cos = 1/(x/r)
1 ÷ x/r is 1•r/x
Thus:-
sec is r/x
