Answer:
8640
Step-by-step explanation:
Answer:
The Lower bound of the confidence interval to the nearest integer = 6
Step-by-step explanation:
<u>Calculate the Lower bound of the confidence interval</u>
<em>First step : Calculate the mean and standard deviation for each groups </em>
<u>Group 1 ( group with music )</u>
N = 9
Total ( ∑x ) = 788
mean = 788 / 9 = 87.55
Variance ( s^2 ) = 39.777
s = = 6.31
<u>Group 2 ( group without music ) </u>
N = 9
∑x = 670
mean = 670 / 9 = 74.44
variance ( s^2 ) = 72.27
s = = 8.50
<em>Next : Calculate the pooled variance , standard error and confidence interval</em>
Pooled variance ( Sp^2 ) : 896.43 / 16 = 56.03
standard error : S ( M1 - M2 ) = √((56.03 / 9) + (56.03 / 9)) = 3.53
confidence interval : μ1 - μ2 = ( M1 - M2 ) ± Ts ( M1 - M2 )
= 13.1111 ± (2.12 * 3.53 )
= ( 5.630 , 20.591 )
The Lower bound of the confidence interval to the nearest integer = 6
The answer is C - f(x) = 3x + 2
Answer:
m(arc CD) = 122°
Step-by-step explanation:
Since, measure of an arc = 2 × (Angle subtended by the arc at the circumference of the circle)
m(arc CD) = 2[m(∠CBD)]
By triangle sum theorem in ΔBCD,
m∠CBD + m∠BDC + m∠DCB = 180°
m∠CBD + 49° + 70° = 180°
m∠CBD = 180° - 119°
m∠CBD = 61°
Therefore, m(arc CD) = 2 × 61°
m(arc CD) = 122°