Christy should make at least 30 bracelets and at most 40 necklaces to maximize profit
<h3>How to determine how many bead of each type of bracelets and necklaces should Christy make to maximize his profit?</h3>
The given parameters can be represented in the following tabular form:
Bracelet (x) Necklace (y) Total
Labor (hour) 0.5 0.75 40
Profit 10 18
From the above table, we have the following:
Objective function:
Max P = 10x + 18y
Subject to:
0.5x + 0.75y <= 40
Because she wants to make at least 30 bracelets, we have:
x >= 30
So, we have:
Max P = 10x + 18y
Subject to:
0.5x + 0.75y <= 40
x >= 30
Express x >= 30 as equation
x = 30
Substitute x = 30 in 0.5x + 0.75y <= 40
0.5 * 30 + 0.75y <= 40
This gives
15 + 0.75y <= 40
Subtract 15 from both sides
0.75y <= 30
Divide by 0.75
y <= 40
Hence, Christy should make at least 30 bracelets and at most 40 necklaces to maximize profit
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Answer:
all FALSE except 3 and 4
Step-by-step explanation:
Hope this helps
-4 is the correct answer
35-12 =25
-4 - ( -27) = -4 + 27 =23
The total number of fish bought was 320. And you know she bought two types of fish. The best way to solve this is guess and check. It would be the fastest. So she bought 7 times as many trigger-fish as parrot fish that means the number of trigger-fish bought was 7p. This means 320 = 7p +p. So all you do is take educated guesses for the number of parrot fish and check if it is right. So if she bought 50 parrot fish. 7(50) + 50 = 400. Close but a bit high. Lets keep guessing. 7(35) + 35 = 245. So now we know the answer is between 50 and 35. So lets try 40. 7(40) + 40 =320. That works so we know she bought 40 parrot fish and 280 trigger-fish.
