Let x and y be the two integers.
The sum of the integers is x+y while the difference is x-y assuming x is larger than y.
If x+y > x-y, then
x+y > x-y
x+y-x > x-y-x
y > -y
y+y > -y+y
2y > 0
2y/2 > 0/2
y > 0
So as long as y is positive, this makes the sum greater than the difference
For example, if x = 10 and y = 2, then
x+y = 10+2 = 12
x-y = 10-2 = 8
clearly 12 > 8 is true
If y is some negative number (say y = -4), then
x+y = 10+(-4) = 10-4 = 6
x-y = 10-(-4) = 10+4 = 16
and things flip around
Saying a blanket statement "the sum of two integers is always greater than their difference" is false overall. If you require y to be positive, then it works but as that last example shows, it doesn't always work.
So to summarize things up, I'd say the answer is "no, the statement isn't true overall"
Answer:
No Solution
Step-by-step explanation:
The equations given are:
x-2y=14
14x-2y=14
The only solution to this system is (0, -7) and therefore there is No Solution.
Answer:
the question you typed is wrong but that on the picture is correct and the correct table which satisfied the equation y =1/4x + 7 is table C
Answer:
2:16 i guess
There's no "possible answers"
Step-by-step explanation:
Answer:
<h2>
11.11 square yard </h2>
Step-by-step explanation:
Step one:
given data
charges=$90
installation=$9 per square yard
total cost of installation= $810
let x represents the number of square feet
Step two:
The expression for the installation cost is given as
810=9x+90------------1
solve for x, collect like terms
810-90=9x
720=9x
divide both sides by 9 we have
x=720/9
x=11.11 square yard
