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artcher [175]
3 years ago
7

Find the missing dimension of the cylinder. Round your answer to the nearest whole number.

Mathematics
2 answers:
Lady_Fox [76]3 years ago
8 0

Answer:

97.7 cm

Step-by-step explanation:

The volume of a cylinder is given by the equation

V=\pi r^2 h

where:

r is the radius of the cylinder

h is the height of the cylinder

V is the volume

In this problem, we know that the volume of the cylinder is

V=600,000 cm^3

Here we are not given the height; here, let's assume it is

h = 20 cm

Therefore, we can re-arrange the equation to find the missing dimension, which is the radius of the cylinder:

r=\sqrt{\frac{V}{\pi h}}=\sqrt{\frac{600,000}{\pi (20)}}=97.7 cm

elena-s [515]3 years ago
7 0

Answer:

<h2>The missing value is the height, and it's equal to 746 centimeters, approximately.</h2>

Step-by-step explanation:

The complete question is

<em>Find the missing dimension of the cylinder. Round your answer to the nearest whole number. Volume = 10,000π in. The radius is 16</em>

A cylinder volume is defined by

V= \pi r^{2} h

Where V=600,000 }cm^{3} and r=16cm.

Replacing given values, we have

600,000=\pi (16)^{2}h

Solving for the height, we have

h=\frac{600,000}{\pi 256} \approx \frac{600,000}{803.84} \approx  746

Therefore, the missing value is the height, and it's equal to 746 centimeters, approximately.

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Please help me!<br> Find the number x such that f(x) =1
STatiana [176]

Answer:

D

Step-by-step explanation:

We have the piecewise function:

f(x) = \left\{        \begin{array}{ll}            -\frac{1}{2}x-1 & \quad x \leq -2 \\            x & \quad x > -2        \end{array}    \right.

And we want to find x such that f(x)=1.

So, let's substitute 1 for f(x):

1 = \left\{        \begin{array}{ll}            -\frac{1}{2}x-1 & \quad x \leq -2 \\            x & \quad x > -2        \end{array}    \right.

This has two equations. So, we can separate them into two separate cases. Namely:

1=-\frac{1}{2}x-1\text{ or } 1=x

Let's solve for x in each case.

Case I:

We have:

1=-\frac{1}{2}x-1

Add 1 to both sides:

2=-\frac{1}{2}x

Let's cancel out the fraction by multiplying both sides by -2. So:

2(-2)=(-2)\frac{-1}{2}x

The right side cancels:

-4=x\\

Flip:

x=-4

So, x is -4.

Case II:

We have:

1=x

Flip:

x=1

This is the solution for our second case.

So, we have:

x_1=-4\text{ or } x_2=1

Now, can check to see if we have to to remove solution(s) that don't work.

Note that x=-4 is the solution to our first equation.

The first equation is defined only if x is less than -2.

-4 <em>is </em>less than -2. So, x=-4 is indeed a solution.

x=1 is the solution to our second equation.

The second equation is defined only if x is greater than or equal to -2.

1 <em>is</em> greater than or equal to -2. So, x=1 is <em>also </em>a solution.

Therefore, our two solutions are:

x_1=-4\text{ or } x_2=1

Out of our answer choices, we can pick D.

And we're done!

7 0
3 years ago
Find the value of x<br> Please help...no links please
OverLord2011 [107]

Answer:

x=1

Step-by-step explanation:

(7x-1)+(2x-1)=7

7x+2x-1-1=7

7x+2x=7+1+1

9x=9

9x/9 = 9/9

x=1

5 0
3 years ago
Please answer this question now in two minutes
Ira Lisetskai [31]

Answer:

the correct answer is (b).........

6 0
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Oduvanchick [21]
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3 years ago
William doubled the amount of money he had after raking leaves. Now he has $24.50. How much money did he hav before he doubled i
ki77a [65]

Answer:

x=8.16

Step-by-step explanation:

x=the money before

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3x=24.50

x=8.16

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3 years ago
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