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padilas [110]
3 years ago
9

Financial planning does or does not require preparation

Mathematics
1 answer:
slega [8]3 years ago
4 0

financial planning does require preparation.

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What’s the domain and range
Softa [21]

Answer:

domain is x range is y

Step-by-step explanation:

4 0
3 years ago
Help me out , please I forgot how to do this mathematics
netineya [11]

Answer:

C

Step-by-step explanation:

sorry if I'm wrong-

7 0
2 years ago
On a coordinate plane, parallelogram R S T U has points (negative 4, 4), (2, 6), (6, 2), and (0, 0). What is the area of paralle
Ad libitum [116K]

Answer:

The area of the parallelogram is;

32 square units

Step-by-step explanation:

The given parameters are;

The coordinates of the parallelogram RSTU = R(-4, 4), S(2, 6), T(6, 2), and U(0, 0)

We note that the area of a parallelogram = Base length × Height

From the drawing of the parallelogram RSTU, we have;

The base length = The length of \overline {TU} = The length of \overline {SR} = √((2 - (-4))² + (6 - 4)²) = 2·√10

The height of a parallelogram is perpendicular to its base length = The line \overline {VT}

∴ Where, the slope of the base length = m, the slope of the height = -1/m

The slope, 'm' of \overline {SR} = (6 - 4)/(2 - (-4)) = 1/3

Therefore, the slope of the height = -1/(1/3) = -3

We note that a point on the height is the point 'T', therefore, the equation of the line in point and slope form is therefore;

y - 0 = -3·(x - 0)

∴ y = -3·x

Therefore, the coordinates of the point 'V' is given by the simultaneous solution of the equations of \overline {SR} and \overline {VT}

The equation of the line \overline {SR} in point and slope form from the point 'R' and the slope 'm = 1/3' is given as follows;

y - 4 = (1/3) × (x - (-4)) = (1/3) × (x + 4)

y = x/3 + 4/3 + 4 = x/3 + 16/3

y = x/3 + 16/3

We then have the coordinate at the point 'V' (x, y) is given as follows;

-3·x = x/3 + 16/3

-9·x = x + 16

-10·x = 16

x = -16/10 = -1.6

x = -1.6

∴ y = -3·x = -3 × -1.6 = -4.8

y = 4.8

The coordinate at the point, V = (-1.6, 4.8)

The length of the line \overline {VT} = The height of the parallelogram = √((-1.6 - 0)² + (4.8 - 0)²) = 8/5·√10

The height of the parallelogram = 8/5·√10

The area of the parallelogram, A = Base length × Height

∴ A = 2·√(10) × 8/5·√(10) = (16/5) × 10 = 32

The area of the parallelogram, A =  32 square units.

6 0
3 years ago
Read 2 more answers
what in a equation to represent the relationship "a number decreased by negative 7 and is the same thing as 48
murzikaleks [220]
I think it would be n-(-7)=48
6 0
3 years ago
Help with 8 and 9??? Please help me out! Correct answers please
Ipatiy [6.2K]

Answer:

  8.  (-∞, 0) ∪ (0, 1/3) ∪ (1/3, ∞)

  9.  f(g(x)) = 4x/(1+6x)

Step-by-step explanation:

8. For f(g(x)) to be defined, g(x) must be defined and f(g(x)) must be defined.

g(x) will be defined for all x≠0. f(g(x)) will be defined for g(x)≠4. Solving g(x)=4, we find the value of x is 1/3. (The answer choices give a clue.)

So, the domain of f(g(x)) is all x that is not 0 or 1/3. Only one answer choice makes those particular exclusions:

  (-∞, 0) ∪ (0, 1/3) ∪ (1/3, ∞)

__

9. Substituting the definition of g(x) into the expression for f(x), we get ...

\displaystyle (f\circ g)(x)=f(g(x))=\frac{2}{g(x)+3}=\frac{2}{\frac{1}{2x}+3}\\\\=\frac{2}{\left(\frac{1+6x}{2x}\right)}\\\\(f\circ g)(x)=\frac{4x}{1+6x}

4 0
3 years ago
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