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bija089 [108]
3 years ago
13

HELPPPP

Mathematics
1 answer:
yawa3891 [41]3 years ago
3 0

Answer:

It 13

Step-by-step explanation:

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2 years ago
A decimal that would be more than a half
Reika [66]

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So basically anything higher than .5 would be x>.5  so it has to be greater than or equal to .51

Step-by-step explanation:

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3 years ago
How to solve this (b) ???​
vladimir1956 [14]

(b). → Simplify: [{5^(x-+1) + 5^x}/{6×5^x}]

= [{5^(x+1+x)}/{6×5^x}]

= [{5^(2x+1)}/{6×5^x}]

= [{5^(2x+1)}/{6×5^x}]

= [{5^(2x+1-x)}/6]

= [{5^(x+1)}/6]Ans.

(c). 4a³b²

= 4(3)³(-2)²

Since, a = 3 and b = -2.

so,

= 4(3*3*3)(-2*-2)

= 4(27)(4)

= 108(4)

= 432Ans.

<u>also</u><u> </u><u>read</u><u> similar</u><u> questions</u><u>:</u> simplify 6/x-6+3x/x+5-1/(x-6)(x+5)..

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simplify the equation simplify x^5/8/x^1/6..

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2 years ago
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