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gizmo_the_mogwai [7]
2 years ago
14

P lease help me. I need fast results please!!!

Mathematics
2 answers:
Vika [28.1K]2 years ago
6 0
1.you would do (4-2-20+1)x and then calculate that and it’s -17x
2. 2/7x-14x= -96/7x or 13.71429
3.collect like terms and you get -8+3x
4.-2-4x+3.8x-x=-2-1.2x

so answers are
1.-17x
2.-96/7
3.-8+3x
4.-2-1.2x
masha68 [24]2 years ago
5 0

Answer:

a 17x

b -97/7x

c -8+3x

d 0.4x

Step-by-step explanation:

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A travel agent is booking trips for tourists who travel from New York to Chicago. Tourists have three choices for how to travel
Hitman42 [59]

List all the different combinations with total cost:

Airplane  + van = 350 + 60 = $410

Airplane  + cab = 350 + 40 = $390

Bus + van = 150 + 60 = $210

Bus + cab = 150 + 40 = $190

Train + van = 225 + 60 = $285

Train + cab = 225 + 40 = $265

There are 6 different combinations.

There are 2 that are more than $300

The probability would be quantity higher than 300 / total combinations.

Probability = 2/6 = 1/3

4 0
2 years ago
Using appreciate property -2/3 × 3/5 + 5/2 - 3/5 × 1/6 ​
o-na [289]

Answer:

The answer for your question is 2.

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
How many kilograms of tin will be required to make 250 kg of an alloy, if the alloy must contain 81% copper, 14% tin and 5% lead
uysha [10]

Answer:

35

Step-by-step explanation:

all are obeying a constant ratio

  • copper 81
  • tin 14⇒?
  • lead 5
  • total 100 ⇒250
  • ?=250*14/100=35
5 0
2 years ago
Read 2 more answers
A) a shopkeeper buys a camera for $300 and sells it at $360. Calculate the percentage profit.
Lilit [14]
A) profit/original price x100 =percentage profit

(Profit: 360-300=$60)

=60/300 x100
=20%

b) two cameras (original price): 300x2= $600
two cameras (price sold): 360x2 = $720

Profit without discount: 720-600= $120

120-100= $20 discount

20/720 x100 =2.78%
4 0
1 year ago
Read 2 more answers
1) A family consisting of three persons—A, B, and C—goes to a medical clinic that always has a doctor at each of stations 1, 2,
crimeas [40]

Answer:

Step-by-step explanation:

Let us record the station number 1, 2 or 3 for each family member A, B or C.

I am attaching a table containing total outcomes. Outcomes are presented along rows while the assigned station to each member is written along columns. For ease of understanding, 1 3 2 in the table should be interpreted as family member A being assigned to station 1, member B to station 3 and member C to station number 2, respectively.

From table it is clear that the total outcomes possible are 27.

We know that, probability can be defined as,

PROBABITILY = \frac{NUMBER\;OF\;DESIRED\;OUTCOMES}{TOTAL\;NUMBER\;OF\;OUTCOMES}

a) All Members Assigned to the Same Station.

Cases for all members being assigned to same station are as follows:

[1 1 1], [2 2 2], [3 3 3] (outcome number 1, 14 and 27 in the table).

Therefore,

PROBABILITY\;(Case\;a) = \frac{3}{27}\\\\PROBABILITY\;(Case\;a) = 0.111

b) At Most Two Members Assigned to the Same Station.

It means that maximum of 2 members can have the same station. Cases for this situation are as follows:

[1 1 2], [1 1 3], [1 2 1], [1 2 2], [1 3 1], [1 3 3], [2 1 1], [2 1 2], [2 2 1], [2 2 3], [2 3 2],

[2 3 3], [3 1 1], [3 1 3], [3 2 2], [3 2 3], [3 3 1], [3 3 2]

(outcome number 2, 3, 4, 5, 7, 9, 10, 11, 13, 15, 17, 18, 19, 21, 23, 24, 25 and 26 in the table).

Therefore,

PROBABILITY\;(Case\;b) = \frac{18}{27}\\\\PROBABILITY\;(Case\;b) = 0.666

c) All Members Assigned to a Different Station.

For this scenario, we have the following results:

[1 2 3], [1 3 2], [2 1 3], [2 3 1], [3 1 2], [3 2 1] (outcome number 6, 8, 12, 16, 20 and 22 in the table).

Therefore,

PROBABILITY\;(Case\;c) = \frac{6}{27}\\\\PROBABILITY\;(Case\;c) = 0.222

3 0
3 years ago
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