All categories

4 years ago

Write the period that has the number 913

2 answers:

4 0

The answer is in the thousands group. Its the way they word the problem that complicates it. 913,256 256 being the ones group 913 being the thousands group. So the name of the period with 913, is the thousands group

Elena-2011 [213]4 years ago

3 0

The answer is actually in the thousands group

You might be interested in

Find x step by step (10 points)

AleksandrR [38]

Answer:

$\sqrt{(n-m)(n+m)}$ & $-\sqrt{(n-m)(n+m)}$

Step-by-step explanation:

1) Subtract $m^{2}$ from both sides. This should leave you with $x^{2}=n^{2}-m^{2}$ .

2) Square root both sides. This should leave you with $x=\sqrt{n^2-m^2}$ & $x=-\sqrt{n^2-m^2}$ .

You can stop here if this is what the problem is asking for. However, it is not fully simplified.

3) Factor the equation. This should leave you with $\sqrt{(n-m)(n+m)}$ & $-\sqrt{(n-m)(n+m)}$ .

4 0

3 years ago

Read 2 more answers

An oblique prism with a square base of edge length x United has a volume of 1/2 x3 cubic units. Which expression represents the

aleksklad [387]

Answer:

The answer is x units.

Step-by-step explanation:

We are tasked to solve for the expression that represents the height of the prism. We are given with the following values:

length = x² units

volume = x³ units

We will use the formula below:

V = length x height

x³ = x² * height

height = x³/x units

height = x units

The answer is x units.

7 0

3 years ago

Read 2 more answers

Joshua and Crystal opened

Stells [14]

Answer:

Joshua's account had a greater change.

Step-by-step explanation:

Both accounts had $100

Joshua's account now has $67.25 which means he used $32.75

Crystal's account now has $131.97 which means he saved $31.97.

Joshua had a greater change of balance.

7 0

3 years ago

Translate each of these statements into logical expressions by using quatifiers and predicates with one or two variables. (a) A

nikdorinn [45]

Answer:

a) $A = \{\exists x \in M, \exist y \in U\,|\,xGy \}$ , b) $B = \{\exists x \in M,\,\exists y \in H\,|\,xMy \}$ , c) $C = \{\forall x \in M\,|\,xI \}$ , d) $D = \{\exists x \in M,\,\forall y \in U\,|\,xJy \}$ , e) $E = \{\exists x \in M, \forall y \in V, V \subseteq U\,|\,xJy \}$

Step-by-step explanation:

a) x - A student, M - Set of students of discrete math class, G - has lived in, y - Florida, U - Set of states of the United States of America.

$A = \{\exists x \in M, \exist y \in U\,|\,xGy \}$

b) x - A student, M - Set of students of discrete math class, y - A perfect grade, H - Midterm I.

$B = \{\exists x \in M,\,\exists y \in H\,|\,xMy \}$

c) x - A student, M - Set of students of discrete math class, I - loves discrete math.

$C = \{\forall x \in M\,|\,xI \}$

d) x - A student, M - Set of students of discrete math class, J - has been in, y - a state, U - Set of states of the United States of America.

$D = \{\exists x \in M,\,\forall y \in U\,|\,xJy \}$

e) x - A student, M - Set of students of discrete math class, J - has been in, y - a city, V - At least one state of the United States of America, U - Set of states of the United States of America.

$E = \{\exists x \in M, \forall y \in V, V \subseteq U\,|\,xJy \}$

5 0

3 years ago

find the number of terms in an AP given that its first and last terms are 13 and - 23 respectively and that its common differenc

Leokris [45]

Answer:

There are 17 terms in the sequence

Step-by-step explanation:

Arithmetic Sequence

An arithmetic sequence is a list of numbers with a definite pattern by which each term is calculated by adding or subtracting a constant number called common difference to the previous term. If n is the number of the term, then:

$a_n=a_1+(n-1)r$