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antiseptic1488 [7]
4 years ago
6

A roller coaster car is traveling on a track without any friction or added energy. The people, car, and track of the roller coas

ter can be analyzed as a single . The total amount of in the roller coaster system is the same at all times. Any increase in the car’s kinetic energy equals a decrease in the system’s .
Physics
2 answers:
Harlamova29_29 [7]4 years ago
3 0

Answer:

This might not be right but i think it is "Speedway Coasters, Inc., reserves the right to exact a $50.00 fine"

Explanation:

tensa zangetsu [6.8K]4 years ago
3 0

System

energy

potential energy

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A piano string having a mass per unit length equal to 5.00× 10⁻³kg / m is under a tension of 1350N . Find the speed with which a
DiKsa [7]

Based on the mass per unit length and the tension, the speed that the wave travels on this string is 519.615 m/s.

<h3>What is the speed?</h3><h3 />

The speed that the wave travels can be found as:

Velocity² = Tension / Mass per length

Solving gives:

Velocity² = 1,350 / 0.005

Velocity² = 270,000

Velocity = √270,000

= 519.615 m/s

Find out more on the speed of a wave at brainly.com/question/12215474

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8 0
2 years ago
An ideal air-filled parallel plate capacitor with plate a separation of 4.0 cm has a plate area of 0.040 m2. what is the capacit
irga5000 [103]

An ideal air-filled parallel plate capacitor with plate a separation of 4.0 cm has a plate area of 0.040 m2. what is the capacitance of this capacitor with air between these plates<u> 8.9 pF.</u>

An ideal air-filled parallel-plate capacitor has round plates and carries a fixed amount of equal but opposite charge on its plates.

The capacitance of a parallel plate capacitor depends on area of each plate, dielectric medium between the plates and distance between the plates.

The amount of energy stored in a plate capacitor is given by

⇒ U = \frac{Q^{2}}{2C},

where, Q is the stored charge and C is the capacitance,

To learn more about parallel plate capacitor, here

brainly.com/question/12733413

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7 0
2 years ago
5. Calculate the speed of Charlie who runs to the store 5 kilometers away in 40<br> minutes
exis [7]
This depends on what units you need to convert to, but the answer would be approximately 2.083 m/s.

5km/40min = 5000m/40min = 5000m/2400s = 2.083 m/s
7 0
3 years ago
A boat is moving towards east with a velocity 4m/s with respect to still water and the river is flowing towards north with veloc
poizon [28]
Refer to the figure below.

The velocity diagram adds the speed of the boat (due east) as a vector to the combined speed of the water and the wind (due north) to obtain the velocity of the flag, at an angle θ,  counterclockwise from the eastern direction.

By definition,
tan θ = 8/4 = 2
θ = arctan(2) = 63.4°

Answer:
The flag blows in a direction which is 63.4° measured counterclockwise from the eastern direction.

4 0
3 years ago
An automobile traveling 95 km/h overtakes a 1.30-km-long train traveling in the same direction on a track parallel to the road.
SOVA2 [1]

Answer:

Same direction: t=234s; d=6.175Km

Opposite direction: t=27.53s; d=0.73Km

Explanation:

If the automobile and the train are traveling in the same direction, then the automobile speed relative to the train will be v_{AT}=v_A-v_T (<em>the train must see the car advancing at a lower speed</em>), where v_A is the speed of the automobile and v_T the speed of the train.

So we have v_{AT}=(95km/h)-(75Km/h)=20Km/h.

So the train (<em>anyone in fact</em>) will watch the automobile trying to cover the lenght of the train L at that relative speed. The time required to do this will be:

t = \frac{L}{v_{AT}} = \frac{1.3Km}{20Km/h} = 0.065h=234s

And in that time the car would have traveled (<em>relative to the ground</em>):

d=v_At=(95Km/h)(0.065h)=6.175Km

If they are traveling in opposite directions, <u>we have to do all the same</u> but using v_{AT}=v_A+v_T (<em>the train must see the car advancing at a faster speed</em>), so repeating the process:

v_{AT}=(95km/h)+(75Km/h)=170Km/h

t = \frac{L}{v_{AT}} = \frac{1.3Km}{170Km/h} = 0.00765h=27.53s

d=v_At=(95Km/h)(0.00765h)=0.73Km

5 0
3 years ago
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