Based on the mass per unit length and the tension, the speed that the wave travels on this string is 519.615 m/s.
<h3>What is the speed?</h3><h3 />
The speed that the wave travels can be found as:
Velocity² = Tension / Mass per length
Solving gives:
Velocity² = 1,350 / 0.005
Velocity² = 270,000
Velocity = √270,000
= 519.615 m/s
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An ideal air-filled parallel plate capacitor with plate a separation of 4.0 cm has a plate area of 0.040 m2. what is the capacitance of this capacitor with air between these plates<u> 8.9 pF.</u>
An ideal air-filled parallel-plate capacitor has round plates and carries a fixed amount of equal but opposite charge on its plates.
The capacitance of a parallel plate capacitor depends on area of each plate, dielectric medium between the plates and distance between the plates.
The amount of energy stored in a plate capacitor is given by
⇒ U =
,
where, Q is the stored charge and C is the capacitance,
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This depends on what units you need to convert to, but the answer would be approximately 2.083 m/s.
5km/40min = 5000m/40min = 5000m/2400s = 2.083 m/s
Refer to the figure below.
The velocity diagram adds the speed of the boat (due east) as a vector to the combined speed of the water and the wind (due north) to obtain the velocity of the flag, at an angle θ, counterclockwise from the eastern direction.
By definition,
tan θ = 8/4 = 2
θ = arctan(2) = 63.4°
Answer:
The flag blows in a direction which is 63.4° measured counterclockwise from the eastern direction.
Answer:
Same direction: t=234s; d=6.175Km
Opposite direction: t=27.53s; d=0.73Km
Explanation:
If the automobile and the train are traveling in the same direction, then the automobile speed relative to the train will be
(<em>the train must see the car advancing at a lower speed</em>), where
is the speed of the automobile and
the speed of the train.
So we have
.
So the train (<em>anyone in fact</em>) will watch the automobile trying to cover the lenght of the train L at that relative speed. The time required to do this will be:

And in that time the car would have traveled (<em>relative to the ground</em>):

If they are traveling in opposite directions, <u>we have to do all the same</u> but using
(<em>the train must see the car advancing at a faster speed</em>), so repeating the process:


