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posledela
2 years ago
13

A boy weighs 40 kilograms. He runs at a velocity of 4 meters per second north. Which is his momentum?

Physics
2 answers:
Andrei [34K]2 years ago
5 0

Answer:

160 kilogram meters per second north

Explanation:

Bogdan [553]2 years ago
4 0
The boy's momentum is 160 kg*m/s north.

The formula of momentum is p = mv, where p is momentum.
p = 40 kg * 4m/s north
p =160 kg*m/s north

<span>Thank you for posting your question. I hope you found what you were after. Please feel free to ask me more.</span>


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A car of weight 300N moved through a distance of 10m when pushed by 3 students
Sati [7]

The work done by the three students is 3,000 J.

The energy transferred in the process is 3,000 J.

<h3>What is work done?</h3>
  • Work done is the product of force and distance moved by the object.

W = Fd

The work done by the three students is calculated as follows;

W = 300 x 10

W = 3,000 J

<h3>What is energy transfer?</h3>
  • This is means by which energy is converted from one form to another.

The energy transferred in the process is determined by work energy theorem.

E = W

E = 3,000 J

Learn more about work-energy theorem here: brainly.com/question/22236101

3 0
2 years ago
A light bulb uses 0.5 amperes from a source of 120 volts. How much power is used by the bulb? 
Sladkaya [172]

Power = voltage(V) * current(I)

          = 120 * 0.5

Power = 60 watts

8 0
3 years ago
An aluminum "12 gauge" wire has a diameter d of 0.205 centimeters. The resistivity ρ of aluminum is 2.75×10−8 ohm-meters. The el
Alborosie

Answer:

I = 4.75 A

Explanation:

To find the current in the wire you use the following relation:

J=\frac{E}{\rho}      (1)

E: electric field E(t)=0.0004t2−0.0001t+0.0004

ρ: resistivity of the material = 2.75×10−8 ohm-meters

J: current density

The current density is also given by:

J=\frac{I}{A}        (2)

I: current

A: cross area of the wire = π(d/2)^2

d: diameter of the wire = 0.205 cm = 0.00205 m

You replace the equation (2) into the equation (1), and you solve for the current I:

\frac{I}{A}=\frac{E(t)}{\rho}\\\\I(t)=\frac{AE(t)}{\rho}

Next, you replace for all variables:

I(t)=\frac{\pi (d/2)^2E(t)}{\rho}\\\\I(t)=\frac{\pi(0.00205m/2)^2(0.0004t^2-0.0001t+0.0004)}{2.75*10^{-8}\Omega.m}\\\\I(t)=4.75A

hence, the current in the wire is 4.75A

4 0
3 years ago
Question 1 (1 point)
Juli2301 [7.4K]

Hello!

\large\boxed{800Ns}

Remember that impulse is equivalent to:

Impulse = force (N) × time (s)

Plug in the given force and time:

Impulse = 25 × 32

Impulse = 800 Ns

3 0
2 years ago
A mixture of gas expands from 0.03m³ to 0.06m³ at constant pressure of 1MPa &amp; absorbs energy of 84 J. Calculate the change i
leonid [27]

Answer:54 kj

Explanation:P1 = P2 = 1000 kPa

1Q2 = 84 kJ

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= 1000 (0.06 – 0.03) = 30 kJ

1Q2 = 1W2 + 1U2

U2 – U1= 1Q2 – 1W2 = 84 – 30 = 54 kJ

4 0
2 years ago
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