4 years ago

How to find the density of an irregular object that floats?

1 answer:

meriva4 years ago

6 0

The most accurate way is to use water displacement

You might be interested in

lora16 [44]

Alpha Centauri is 4.4 lightyears away. Traveling at 1/10 speed of light it would take you 44 years.

3 0

3 years ago

Maru [420]

The force is being pulled my the gravity or it could be a third party thing like a black hole you feel me

6 0

3 years ago

Georgia [21]

Answer:

1. B

2. D

Explanation:

7 0

4 years ago

NemiM [27]

0 N. It's being pushed up the same amount it's being pushed down, so it cancels out.

6 0

3 years ago

kiruha [24]

Answer:

Range will become 4 times of initial range

Explanation:

Let the velocity of projection is u

And angle at which projectile is projected is $\Theta$

And acceleration due to gravity is $g\ m/sec^2$

So range of projectile is equal to $R=\frac{u^2sin2\Theta }{g}$ ........eqn 1

Now in second case it is given that velocity of launching is doubled

So new velocity $u_{new}=2u$

So new range will be equal to $R_{new}=\frac{(2u)^2sin2\Theta }{g}=\frac{4u^2sin2\Theta }{g}$ .....eqn 2

Now dividing eqn 2 by eqn 1

$\frac{R_{new}}{R}=\frac{4u^2sin2\Theta }{g}\times \frac{g}{u^2sin2\Theta }$

$R_{new}=4R$

So if we double the initial launch speed then range will become 4 times

4 0

4 years ago