Answer:
Step-by-step explanation:
(6e-3f-3/4) contains two terms which do not involve fractions and one fractional term (3/4).
We can safely remove the parentheses. Then:
(6e-3f-3/4) => 6e - 3f - 3/4
That is "an equivalent expression."
We could go further and create one equivalent fraction. Multiply the first two terms by 4/4, obtaining:
24e 12f 3 24e - 12f - 3 3(8e - 4f - 1
------ - ------ - ----- => ---------------------- => -------------------
4 4 4 4 4
Other equivalent expressions exist here.
Answer:
26.8907563 or if your rounding it then 26.7
Step-by-step explanation:
Since the measure of angle
is 
The measure of its reference angle = 
=
Now we have to compute the value of 


The value of (
) lies in the fourth quadrant. In fourth quadrant, the value of tan is always negative.
So, 

= -1.
Because 1023.68 is 112% of the loan, you can divide by 1.12 to get 914, which is the answer
Answer:

Step-by-step explanation:
