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3 years ago

6

Given that / and /, which postulate or theorem can be used to show that all 3 center triangles in the Antigua and Barbuda flag a

re similar?

2 answers:

Svetllana [295]3 years ago

6 0

Actually, the answer is ASA postulate!!!! I just took the county geometry quiz and got it correct

MrRissso [65]3 years ago

4 0

Given that we assume that all the bases of the triangles are parallel.

We can use AAA or Angle-Angle-Angle to prove that these triangles are similar.

Each parallel line creates the same angle when intersecting with the same side.
For example:
The bases of each triangle cross the left side of all the triangle.
Each angle made by the intersecting of the the parallel base and the side are the same.
Thus, each corresponding angle of all the triangles are congruent.
If these angles are congruent, then we have similar triangles.

You might be interested in

The line of symmetry for the quadratic equation y = ax2 - 2x - 3 is x = 1. What is the value of "a"?

timama [110]

Y = a(x - h)² + k • (h, k) is the vertex • x = h is line of symmetry so y = ax² - 2x - 3 y/a = x² - 2/ax - 3/a y/a + 3/a = x² - 2/ax y/a + 4/a= x² - 2/ax + (-1/a)² ← completing the square y/a + 4/a= (x - 1/a)² y/a = (x - 1/a)² - 4/a y = a(x - 1/a)² - 4 so since you've been given h = 1 then 1/a = 1 and so a = 1

6 0

3 years ago

Read 2 more answers

A demographer wants to measure life expectancy in countries 1 and 2. Let μ1 and μ2 denote the mean life expectancy in countries

Art [367]

Answer:

For this case we want to test if life expectancy in country 1 is more than 10 years lower than in country 2, (alternatibe hypothesis), so then the system of hypothesis are:

Null hypothesis: $\mu_1 \leq \mu_2 -10$

Alternative hypothesis: $\mu_1 > \mu_2 -10$

Or equivalently:

Null hypothesis: $\mu_1 - \mu_2 \leq 10$

Alternative hypothesis: $\mu_1 - \mu_2 >10$

Step-by-step explanation:

Previous concepts

A hypothesis is defined as "a speculation or theory based on insufficient evidence that lends itself to further testing and experimentation. With further testing, a hypothesis can usually be proven true or false".

The null hypothesis is defined as "a hypothesis that says there is no statistical significance between the two variables in the hypothesis. It is the hypothesis that the researcher is trying to disprove".

The alternative hypothesis is "just the inverse, or opposite, of the null hypothesis. It is the hypothesis that researcher is trying to prove".

Solution to the problem

For this case we want to test if life expectancy in country 1 is more than 10 years lower than in country 2, (alternatibe hypothesis), so then the system of hypothesis are:

Null hypothesis: $\mu_1 \leq \mu_2 -10$

Alternative hypothesis: $\mu_1 > \mu_2 -10$

Or equivalently:

Null hypothesis: $\mu_1 - \mu_2 \leq 10$

Alternative hypothesis: $\mu_1 - \mu_2 >10$

7 0

3 years ago

Does anyone know the answer

il63 [147K]

Answer:

Both angles B and C are equal to 40°

Step-by-step explanation:

The diagram tells you that the triangle is an isosceles triangle. From this we know that angles B and C will be equal to each other. To find what the angle measures are, we are going to set the two given expressions equal to each other, solve for x, and the plug x back in to get the two angle measures.

$2x+10=3x-5\\10=x-5\\15=x$

Now we are going to plug x back into each expression to solve for angles B and C.

Angle B

$2x+10$ ⇒ $2(15)+10=40$

Angle C

$3x-5$ ⇒ $3(15)-5=40$

Both angles B and C are equal to 40°

7 0

3 years ago

please do the steps Solve for d: 1/6d-8=5/8 2. Solve for x: 3x-4+5x=10-2z 3. Solve for c: 7(c-3)=14 4. Solve for m: 11(m/22+3/44

xeze [42]

Answer:

d = 55.5

x = 1

c = 11

m = $\frac{1}{122}$

k = $\frac{a}{(c + 5)}$

Step-by-step explanation:

Sorry, the formatting is slightly hard to understand, but I think this is what you meant.

Q1.

$\frac{1}{6}$ d - 8 = $\frac{5}{8}$ x 2

Step 1. Simplify.

$\frac{5}{8}$ x 2 = $\frac{5}{8}$ x $\frac{2}{1}$ = $\frac{10}{8}$

Step 2. Cancel out the negative 8.

$\frac{1}{6}$ d - 8 = $\frac{10}{8}$

+ 8 to both sides (do the opposite: $\frac{1}{6}$ d is subtracting 8 right now, but to cancel that out, we will do the opposite of subtraction, i.e. addition)

$\frac{1}{6}$ d = $\frac{10}{8}$ + 8

Step 3. Simplify.

$\frac{10}{8}$ + 8 = $\frac{10}{8}$ + $\frac{8}{1}$ = $\frac{10}{8}$ + $\frac{64}{8}$ = $\frac{74}{8}$ = $\frac{37}{4}$

Step 4. Cancel out the $\frac{1}{6}$ .

$\frac{1}{6}$ d = $\frac{37}{4}$

÷ $\frac{1}{6}$ from both sides (do the opposite: d is multiplied by $\frac{1}{6}$ right now, but to cancel that out, we will do the opposite of multiplication, i.e. division)

÷ $\frac{1}{6}$ = x 6

So....

x 6 to both sides

d = $\frac{37}{4}$ x 6 = $\frac{37}{4}$ x $\frac{6}{1}$ = $\frac{222}{4}$ = $\frac{111}{2}$ = 55.5

Step 5. Write down your answer.

d = 55.5

Q2.

3x - 4 + 5x = 10 - 2x × 3

Step 1. Simplify

3x - 4 + 5x = 3x + 5x - 4 = 8x - 4

10 - 2x × 3 = 10 - (2x × 3) = 10 - 6x

Step 2. Cancel out the negative 6x

8x - 4 = 10 - 6x

+ 6x to both sides (do the opposite - you're probably tired of reading this now - right now it's 10 subtract 6x, but the opposite of subtraction is addition)

14x - 4 = 10

Step 3. Cancel out the negative 4

14x - 4 = 10

+ 4 to both sides (right now it's 14x subtract 4, but the opposite of subtraction is addition)

14x = 14

Step 4. Divide by 14

14x = 14

÷ 14 from both sides (out of the [14 × x] we only want the [x], so we cancel out the [× 14])

x = 1

Step 5. Write down your answer.

x = 1

Q3.

7(c - 3) = 14 × 4

Step 1. Expand the brackets

7(c - 3) = (7 x c) - (7 x 3) = 7c - 21

Step 2. Simplify

14 x 4 = 56

Step 3. Cancel out the negative 21

7c - 21 = 56

+ 21

7c = 56 + 21

7c = 77

Step 4. Cancel out the ×7

7c = 77

÷ 7

c = 77 ÷ 7

c = 11

Step 5. Write down your answer.

c = 11

Q4.

11( $\frac{m}{22}$ + $\frac{3}{44}$ ) = 87m + m × 5

Step 1. Expand the brackets

11( $\frac{m}{22}$ + $\frac{3}{44}$ ) = (11 x $\frac{m}{22}$ ) + (11 x $\frac{3}{44}$ ) = ( $\frac{11}{1}$ x $\frac{m}{22}$ ) + ( $\frac{11}{1}$ x $\frac{3}{44}$ ) = $\frac{11m}{22}$ + $\frac{33}{44}$ = $\frac{m}{2}$ + $\frac{3}{4}$

Step 2. Simplify.

87m + m x 5 = 87m + 5m = 92m

Step 3. Cancel out the add $\frac{3}{4}$

$\frac{m}{2}$ + $\frac{3}{4}$ = 92m

- $\frac{3}{4}$

$\frac{m}{2}$ = 92m - $\frac{3}{4}$

$\frac{m}{2}$ = $\frac{92m}{1}$ - $\frac{3}{4}$

$\frac{m}{2}$ = $\frac{368m}{4}$ - $\frac{3}{4}$

$\frac{m}{2}$ = $\frac{368m - 3}{4}$

Step 4. Cancel out the ÷ 4

$\frac{m}{2}$ = $\frac{368m - 3}{4}$

x 4

2m = 368m - 3

Step 5. Cancel out the 368m

2m = 368m - 3

- 368m

-366m = - 3

Step 6. Cancel out the × -366

-366m = -3

÷ -366

m = $\frac{-3}{-366}$

m = $\frac{1}{122}$

Step 7. Write down your answer.

m = $\frac{1}{122}$

Q5.

ck + 5k = a

Step 1. Factorise

ck + 5k = (c × k) + (5 × k) = (c + 5) x k = k(c + 5)

Step 2. Cancel out the × (c + 5)

k(c + 5) = a

÷ (c + 5)

k = a ÷ (c + 5)

k = $\frac{a}{(c + 5)}$

5 0

4 years ago

Find the scale factor of DEFG to PQRS.

Travka [436]

The scale factor of DEFG to PQRS is 2 to 1 or 2/1 or 2:1

6 0

3 years ago