Answer:
my guess is C- to breathe...but the respiratory system also gets rid of waste, but mainly to help a person breathe
Explanation:
hope this helps
Yes. In the beginning, glycolysis requires 2 ATP molecules.
One ATP allows for the phosphorylation of the glucose molecule to fructose-6-phosphate and another phosphorylation to fructose-1,
6-biphosphate. The fructose-1, 6- bisphosphate
is then cleaved into two glyceraldehyde-3-phosphates that then enter the energy
generating part of the glycolysis biochemical reaction.
Pretty sure the answer would be C, because you need the warm and cold air to mix.
Answer:
a. Determine the allele frequencies of:
f(T) = 0.485 ≅ 0.48
f(t) = 0.515 ≅ 0.52
b. Determine the genotype frequencies of the exposed generation
- F (TT) = 0.21
- F (Tt) = 0.55
- F (tt) = 0.24
the genotype frequencies of the next generation
- F(TT) = 0.23
- F(Tt) = 0.5
- F(tt) = 0.27
Explanation:
Due to technical problems, you will find the complete answer and explanation in the attached files
Exactly 989527/1048576, or approximately 94.37%
Since each trait is carried on a different chromosome, the two traits are independent of each other. Since both parents are heterozygous for the trait, each parent can contribute 1 of a possible 4 combinations of the alleles. So there are 16 possible offspring. I'll use "a", "A", "b", "B" to represent each allele and the possible children are aabb, aabB, aaBb, aaBB, aAbb, aAbB, aABb, aABB, Aabb, AabB, AaBb, AaBB, AAbb, AAbB, AABb, and AABB
Of the above 16 possibilities, there are 7 that are homozygous in an undesired traint and 9 that don't exhibit the undesired trait. So let's first calculate the probability of "what are the chances that all 5 children not exhibiting an undesired trait?" and then subtract that result from 1. So
1-(9/16)^5 = 1 - 59049/1048576 = 989527/1048576 which is approximately 0.943686485 = 94.3686485%
So the answer is exactly 989527/1048576, or approximately 94.37%
