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Ad libitum [116K]
3 years ago
10

PLEASE HELP! WILL REWARD BRAINLIEST TO BEST ANSWER WRITE DOWN INFORMATION. Create all four digit numbers that are divisible by 8

using the digits 1,2,3, and 4
Mathematics
1 answer:
AnnZ [28]3 years ago
7 0

Answer:

Example: 25,216 - the last 2 digits are 16 which is a multiple of 4 so this number is divisible by 4. Using the digits 1, 2, 3, 4, 5 only once, there are only a four combinations that create numbers divisible by 4…..12, 24, 32, 52.

Step-by-step explanation:


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g (15 points) Suppose 42 out of 600 rats exposed to a potential carcinogen develop tumors. A control group of 350 rats not expos
vazorg [7]

Answer:

a) The relative risk is 1.8\overline{846153}

b) The attributable risk is 0.69 \overline{047619}

c) There is a relationship between exposure and tumor risk

Step-by-step explanation:

The number of exposed rats that develop tumors, a = 42

The number of rats exposed to the carcinogen = 600 rats

The number of exposed rats that did not develop tumors, b = 600 - 42 = 558

The number of not exposed rats in the control group = 350 rats

The number of rats that develop tumors in the control group, c = 13 tumors

The number of not exposed rats that did not develop tumors, d = 350 - 13 = 337  rats

a) The relative risk, RR = a/(a + b)/(c/(c + d))

∴ RR = (42/(42 + 558))/(13/(13 + 337)) = 49/26 = 1.8\overline{846153}

b) The attributable risk = (a - c)/a

∴ The attributable risk = (42 - 13)/42 = 0.69 \overline{047619}

c) The odds ratio = (a·b)/(c·d)

∴ The odds ratio = 42 × 558/(13 × 337) = 23439/4381 ≈ 5.35

Given that the result of attributable risk is positive, there is an indication that there is a higher probability to develop tumor when exposed to the potential carcinogen, therefore, there is a relationship between exposure and tumor risk

7 0
3 years ago
On three examinations, you have grades of 85, 78, and 84. There is still a final examination, which counts as one grade In order
Greeley [361]

Answer:

  • It's not possible to earn an A in the course
  • I must have a 73 or MORE to earn a B in the course

Step-by-step explanation:

The average obtained at the end of the course will be:

\frac{85+78+84+x}{4} = av

Where x is the grade obtained in the final examination and av is the final average. To obtain an A, av has to be at least 90, av≥90, and to obtain an B, av has to be at least 80, av≥80

  • Is an A in the course possible?

So, if we get 100 on the final average:

x = 100,

av = (85+78+84+100)/4 = 86,75 and  86,75∠90.

<em>Answer: No, the higher grade obtained would be 86,75.</em>

  • What grade you must have in the final to earn a B in the course

To earn a B, av≥80:

av= \frac{85+78+84+x}{4 \ }\geq  80\\ \frac{247+x}{4}\geq80   \\247+x\geq 80*4\\ x\geq 320-247\\ x\geq 73

<em>Answer: I must have a 73 or MORE to earn a B in the course</em>

6 0
3 years ago
Y = -x + 5<br> Write in standard form. PLEASE SHOW WORK! WILL GIVE BRAINLY!
strojnjashka [21]

Answer:

x+y=5

Step-by-step explanation:

y=-x+5

add x to both sides

x+y=5

8 0
3 years ago
Read 2 more answers
Copy and complete the table of each values for each equation
Aleksandr-060686 [28]

Step-by-step explanation:

Given function is y = –x.

Substitute the values of x in the function and find the values of y.

y = –x

At x = –2,

y = –(–2) = 2

At x = –1,

y = –(–1) = 1

At x = 0,

y = –(0) = 0

At x = 1,

y = –1(1) = –1

At x = 2,

y = –(2) = –2

Now, substitute the values of y in the table.

The image of the table is attached below.

8 0
3 years ago
Question 5 (1 point)
HACTEHA [7]

Answer:

B. \frac{d + 13}{d + 4}

Hope this Helps :)

3 0
3 years ago
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