Answer:
The distance between first and third base is <u>127.27 ft</u>
Step-by-step explanation:
<h3>Given:-</h3>
- A baseball field in a square that is 90 feet on each side
<h3><u>To find:-</u></h3>
- <u>Distance</u><u> </u><u>b/</u><u>w </u><u>first</u><u> </u><u>base </u><u>and </u><u>third</u><u> </u><u>base</u>
<h3>
<u>Explanation</u><u>:</u><u>-</u></h3>
Here, the baseball field is in square each side 90ft so basically we have to find shortest distance b/w first and third base so we will draw a diagonal which form two right-angled triangle with common hypotenuse So we will use Pythagoras Theorem to find the shortest distance and which is also use for two-dimensional navigation.
<h3><u>
Solution:-</u></h3>
The Formula for Pythagoras theorem is
where,
c = hypotenuse
a = length
b = base
Here length and base both are of 90, So putting the value in the formula
c² = a² + b²
c² = 90² + 90²
c² = 8100 + 8100
c² = 16200
c = √16200
c = 127.27ft
Hence, the shortest distance between first and third base is 127.27ft.
Answer:
y=2/3x -3
Step-by-step explanation:
y=mx+c
If the gradient(m) is the same then it's parallel.
The line passes through -3 so the y intercept(c) is -3
16 is the answer b/c 8x4 is 32 and 4x4 is 16 so subtract 32-16=16
Answer:
a) $(
)
b) $(20m + 7080 - 43200/m)
d) m= 36 or m= -60
e) $200
Step-by-step explanation:
Please see the attached pictures for full solution.