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3 years ago

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What measure of central tendency is least representative of the data set known?

1 answer:

Mamont248 [21]3 years ago

5 0

The measure of central tendency that least represents the set of data shown is mean. There is a large outlier in the set of data which results to the skewing of the mean. The mean of the set is 8. The mode is 2 and the median is 3.5, which are better representations of the data.

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Given that ABCD is a rhombus, what is the value of x?<br>(3x - 26)

ExtremeBDS [4]

<h2>The required "option B) $20.75\°$ " is correct.</h2>

Step-by-step explanation:

You can refer figure:

brainly.com/question/4386376

To find, the value of x = ?

We know that,

Consecutive angles are supplementary

The diagonals bisect the angles.

$2x\°+2(3x+7)\°=180\°$

Divided by 2 both sides, we get

⇒ $x\°+(3x+7)\°=90\°$

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Thus, the required "option B) $20.75\°$ " is correct.

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3 years ago

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Prove that an = 4^n + 2(-1)^nis the solution to

olga nikolaevna [1]

Answer:

See proof below

Step-by-step explanation:

We have to verify that if we substitute $a_n=4^n+2(-1)^n$ in the equation $a_n=3a_{n-1}+4a_{n-2}$ the equality is true.

Let's substitute first in the right hand side:

$3a_{n-1}+4a_{n-2}=3(4^{n-1}+2(-1)^{n-1})+4(4^{n-2}+2(-1)^{n-2})$

Now we use the distributive laws. Also, note that $(-1)^{n-1}=\frac{1}{-1}(-1)^n=(-1)(-1)^{n}$ (this also works when the power is n-2).

$=3(4^{n-1})+6(-1)^{n-1}+4(4^{n-2})+8(-1)^{n-2}$

$=3(4^{n-1})+(-1)(6)(-1)^{n}+4^{n-1}+(-1)^2(8)(-1)^{n}$

$=4(4^{n-1})-6(-1)^{n}+8(-1)^{n}=4^n+2(-1)^n=a_n$

then the sequence solves the recurrence relation.

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3 years ago