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Gemiola [76]
3 years ago
14

How do you convert mg to kilograms? How do you convert mg to kilograms? 1 following 7 answers 7 Report Abuse Are you sure you wa

nt to delete this answer? Yes No
Mathematics
1 answer:
scoundrel [369]3 years ago
4 0
Hello there.

<span>How do you convert mg to kilograms?

1e-6
</span>
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7 in.<br> 5 in.<br> 7 in.<br> 5 in.<br> The perimeter?
lana66690 [7]

Answer:

The perimeter is:

24

Step-by-step explanation:

Perimeter is the outside frame of the area. Add the dimensions together to get your answer. Adding:

7+7= 14

5+5= 10

10+14= 24

:) Hope this helps have a wonderful day!

7 0
2 years ago
Read 2 more answers
Find the area of the triangle defined by the coordinates (7, 1), (0, 10), and (9, 4). (To the nearest tenth)
slega [8]

Answer:

  C)  19.5 square units

Step-by-step explanation:

The area from coordinates can be computed as ...

  A = (1/2)|x1(y2 -y3) +x2(y3 -y1) +x3(y1 -y2)|

  = (1/2)|7(10 -4) +0(4 -1) +9(1-10)| = (1/2)|7·6 +9·(-9)|

  = (1/2)|-39| = 39/2 = 19.5

The area of the triangle is 19.5 square units.

4 0
3 years ago
Read 2 more answers
A scientist launched an object upward at a speed of 32 ft per second from a height of 240 feet. The height of the object is mode
QveST [7]

Answer:

B 5 seconds

Step-by-step explanation:

h = 240 + 32t – 16t^2

When is this equation 0

0 = 240 + 32t – 16t^2

Factor out 16

0 = -16(-15-2t+t^2)

   = -16(t^2-2t-15)

What 2 numbers multiply to -15 and add to -2

-5*3 = -15

-5+3 =-2


0 = -16(t-5) (t+3)

Using the zero product property

t-5=0   t+3=0

t=5    t=-3

Since time cannot be negative

t=5 seconds

3 0
4 years ago
The area of a rectangular piece of cardboard is represented by
Liula [17]

This question is solved applying the formula of the area of the rectangle, and finding it's width. To do this, we solve a quadratic equation, and we get that the cardboard has a width of 1.5 feet.

Area of a rectangle:

The area of rectangle of length l and width w is given by:

A = wl

w(2w + 3) = 9

From this, we get that:

l = 2w + 3, A = 9

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\Delta}}{2*a}

x_{2} = \frac{-b - \sqrt{\Delta}}{2*a}

\Delta = b^{2} - 4ac

In this question:

w(2w+3) = 9

2w^2 + 3w - 9 = 0

Thus a quadratic equation with a = 2, b = 3, c = -9

Then

\Delta = 3^2 - 4(2)(-9) = 81

w_{1} = \frac{-3 + \sqrt{81}}{2*2} = 1.5

w_{2} = \frac{-3 - \sqrt{81}}{2*2} = -3

Width is a positive measure, thus, the width of the cardboard is of 1.5 feet.

Another similar problem can be found at brainly.com/question/16995958

5 0
3 years ago
(x^3+3x^2-x-3)÷(x-1) solve using long division must show work​
garik1379 [7]
The answer to the question

6 0
3 years ago
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