Put the equation in standard linear form.

Find the integrating factor.

Multiply both sides by
.

Now the left side the derivative of a product,

Integrate both sides.

On the right side, integrate by parts.

Solve for
.

D = 545.79
r = 48.3
Plug in numbers to corresponding variables
545.79 = t(48.3)
Isolate the t, divide 48.3 from both sides
(545.79)/48.3 = 48.3t/48.3
t = 545.79/48.3
t = 11.3
t = A) 11.3 h
hope this helps
Answer:
y=1/2x-3
Step-by-step explanation:
Discriminant D is given by:
D=b²-4ac
Implication of discriminant is as follows:
D<0 two zeros that are complex conjugate
D=0 one real zero of multiplicity 2
D>0 two distinct real zers
D= (+ve perfet square) two distinct rational zeros
From:
12x^2+10x+5=0
plugging in the equation we get:
10²-4×12×5
=100-240
=-140
thus
D<0
Answer is:
<span>A two irrational solutions </span>
3275 = x * (1+0.075/12)^(12*10)
3275 = x * (2.11206463)
x= 3275/2.11206463 = 1550.6154
x=1550.62
she needs to deposit $1,550.62