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3 years ago

What line passes through (4,-5) ; m=6

Mathematics

1 answer:

tatiyna3 years ago

3 0

Answer:

I cant tell you the answer but think of this formula.

Step-by-step explanation:

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Tony gets paid $5 per hour to babysit his cousin. This

Kaylis [27]

Answer:

Step-by-step explanation:

lets substitute 5 into every equation. (using 5 every time won't work every time ofc)

ok so 5(x+6)=55 would simplify into 5x+30=55 which in this case would be 5(5)+30=55 

and 25 plus 30 (obviously) = 55

so A is the right answer

8 0

2 years ago

People show me your holiday spirit

LenaWriter [7]

Answer:

im the grinch

Step-by-step explanation:

3 0

3 years ago

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I need help with this !! chart

Burka [1]

Answer:

Make coordinates with this table.

Step-by-step explanation:

What I think from these tables is that you can make coordinates with these points. Here are the instructions for you to follow-

See the "y" and "x". These are the axis. So make coordinates with these. Ex- (0,3), (1,5) and so on
Plot these coordinates in a graph paper.
After plotting them, you might find the shape it made.

I hope it helps you.

3 0

3 years ago

If 180° < α < 270°, cos⁡ α = −817, 270° < β < 360°, and sin⁡ β = −45, what is cos⁡ (α + β)?

eduard

Answer:

$cos(\alpha+\beta)=-\frac{84}{85}$

Step-by-step explanation:

we know that

$cos(\alpha+\beta)=cos(\alpha)*cos(\beta)-sin(\alpha)*sin(\beta)$

Remember the identity

$cos^{2} (x)+sin^2(x)=1$

step 1

Find the value of $sin(\alpha)$

we have that

The angle alpha lie on the III Quadrant

The values of sine and cosine are negative

$cos(\alpha)=-\frac{8}{17}$

Find the value of sine

$cos^{2} (\alpha)+sin^2(\alpha)=1$

substitute

$(-\frac{8}{17})^{2}+sin^2(\alpha)=1$

$sin^2(\alpha)=1-\frac{64}{289}$

$sin^2(\alpha)=\frac{225}{289}$

$sin(\alpha)=-\frac{15}{17}$

step 2

Find the value of $cos(\beta)$

we have that

The angle beta lie on the IV Quadrant

The value of the cosine is positive and the value of the sine is negative

$sin(\beta)=-\frac{4}{5}$

Find the value of cosine

$cos^{2} (\beta)+sin^2(\beta)=1$

substitute

$(-\frac{4}{5})^{2}+cos^2(\beta)=1$

$cos^2(\beta)=1-\frac{16}{25}$

$cos^2(\beta)=\frac{9}{25}$

$cos(\beta)=\frac{3}{5}$

step 3

Find cos⁡ (α + β)

$cos(\alpha+\beta)=cos(\alpha)*cos(\beta)-sin(\alpha)*sin(\beta)$

we have

$cos(\alpha)=-\frac{8}{17}$

$sin(\alpha)=-\frac{15}{17}$

$sin(\beta)=-\frac{4}{5}$

$cos(\beta)=\frac{3}{5}$

substitute

$cos(\alpha+\beta)=-\frac{8}{17}*\frac{3}{5}-(-\frac{15}{17})*(-\frac{4}{5})$

$cos(\alpha+\beta)=-\frac{24}{85}-\frac{60}{85}$

$cos(\alpha+\beta)=-\frac{84}{85}$

4 0

3 years ago

There are 112 seats in the school auditorium. There are 7 seats in each row. There are 70 people seated,filling up full rows of

lord [1]

I think 11 rows are empty.

6 0

3 years ago

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