Given:
Volume of toy=231 cm³
Diameter of a hemisphere= 7 cm
cone and hemisphere have equal radius.
radius of hemisphere = radius of cone = 3.5 cm
Height of hemisphere= radius of hemisphere= 3.5 cm
Let H be the height of toy
H= height of cone+ height of hemisphere
H = h + r , ( h = height of cone)
H = h + 3.5
volume of toy = volume of cone + volume of hemisphere
Volume of toy= 1/3πr²h + 2/3πr³
Volume of toy=πr²/3(h+2r)
231 = (22/7)×(3.5)² ×(1/3)(h+2×3.5)
231×3 =( 22×3.5×3.5)/7 (h+7)
h+7 = (231×3×7)/(3.5×3.5×22)
h+7 = (3×3)/(.5×.5×2)
h+7= 900 /50= 90/5= 18
h+7= 18
h=18-7
h= 11 cm
Height of toy = h+r
Height of toy = 11+3.5= 14.5
Height of toy =14.5 cm
Hence, the height of the toy = 13.5 cm
Yes, I can show you how to solve that problem.
Please watch carefully and try to follow me.
I'll go slowly, and you must stop me if I do
anything that's not clear to you.
You said that <u> Rick + 15 = 100</u>
Subtract 15 from each
side of the equation: <em>Rick = 85
</em>
A(n)=ar^(n-1) so
100=4r^9
25=r^9
ln25=9lnr
ln25/9=lnr
r=e^(ln25/9)
a(n)=4e^((n-1)(ln25/9) if you wanted an approximation...
a(n)=4(1.43^(n-1))
Answer:
Step-by-step explanation
You must find the common denominator for all of them.
A is correct. 13 x 2 is 26 and 14 x 2 is 28. Therefore, 13/14 is greater than 25/28.
B is not correct. 4 x 5 is 20 and 9 x 5 is 45. 4/9 is actually less than 21/45.
C is not correct. 5 x 2 is 10 and 6 x 2 is 12. 5/6 is actually less than 11/12.
D is not correct. 4 x 5 is 20 and 5 x 5 is 25. 4/5 is actually less than 8/25.