1) Formula: area = height * base / 2
2) Call x the height:
height = x
base = 2x
3) State the equation:
(x)(2x) = 49 in^2
4) Solve the equation:
2x^2 = 49 in^s
x^2 = (49/2) in^2
x = √(49/2) in
x = 7√2 / 2 in = 3.5 √2 in
5) Solution:
height = 3.5 √2 in and base = 7√2 in
6) Verification: area = (7√2 in) (3.5√2 in) = 49 in^2
Answer: height = 3.5√2 in and base = 7√2 in.
Answer: z < 4
z+4 > 2z
z+4-z > 2z-z ..... Subtract z from both sides
4 > z
z < 4
So the solution set for z is any number that is less than 4, which could be something like z = 2 or z = 3.
The answer would be no solution. It comes out to 56=-49