3k to the 2 power - 10k - 7
1 answer:
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Given that <span>For
a certain model of car the distance 
required to stop the vehicle if
it is traveling at 
mi/h is given by the formula ![d=v+\frac{v^2}{20}, where [tex]d](https://tex.z-dn.net/?f=d%3Dv%2B%5Cfrac%7Bv%5E2%7D%7B20%7D%2C%20where%20%5Btex%5Dd%20)
is measured in feet.
If Kerry wants her stopping distance not to exceed 75 ft, then the range of speeds (in mi/h) can she travel is obtained as follows:
Therefore, the range of speed she can travel is
</span>
If Kerry wants her stopping distance not to exceed 75 ft, then the range of speeds (in mi/h) can she travel is obtained as follows:
Therefore, the range of speed she can travel is
</span>
7) Write the decimal number as a fraction
(over 1)
2.18 = 2.18 / 1
Multiplying by 1 to eliminate 3 decimal places
we multiply top and bottom by 3 10's
Numerator (N)
N = 2.18 × 10 × 10 × 10 = 2180
Denominator (D)
D = 1 × 10 × 10 × 10 = 1000
N / D = 2180 / 1000
Simplifying our fraction
= 2180/1000
= 109/50
= 2 9/50
8)
(over 1)
2.18 = 2.18 / 1
Multiplying by 1 to eliminate 3 decimal places
we multiply top and bottom by 3 10's
Numerator (N)
N = 2.18 × 10 × 10 × 10 = 2180
Denominator (D)
D = 1 × 10 × 10 × 10 = 1000
N / D = 2180 / 1000
Simplifying our fraction
= 2180/1000
= 109/50
= 2 9/50
8)