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Nikolay [14]
3 years ago
5

Please help asap 25 pts

Mathematics
1 answer:
devlian [24]3 years ago
7 0
The answer is B hope this would help you
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MathsWatch Question <br> Please Help
elena-s [515]

Answer:

940 grams

Step-by-step explanation:

5 0
2 years ago
15. Suppose a box of 30 light bulbs contains 4 defective ones. If 5 bulbs are to be removed out of the box.
Naddika [18.5K]

Answer:

1) Probability that all five are good = 0.46

2) P(at most 2 defective) = 0.99

3) Pr(at least 1 defective) = 0.54

Step-by-step explanation:

The total number of bulbs = 30

Number of defective bulbs = 4

Number of good bulbs = 30 - 4 = 26

Number of ways of selecting 5 bulbs from 30 bulbs = 30C5 = \frac{30 !}{(30-5)!5!} \\

30C5 = 142506 ways

Number of ways of selecting 5 good bulbs  from 26 bulbs = 26C5 = \frac{26 !}{(26-5)!5!} \\

26C5 = 65780 ways

Probability that all five are good = 65780/142506

Probability that all five are good = 0.46

2) probability that at most two bulbs are defective = Pr(no defective) + Pr(1 defective) + Pr(2 defective)

Pr(no defective) has been calculated above = 0.46

Pr(1 defective) = \frac{26C4  * 4C1}{30C5}

Pr(1 defective) = (14950*4)/142506

Pr(1 defective) =0.42

Pr(2 defective) =  \frac{26C3  * 4C2}{30C5}

Pr(2 defective) = (2600 *6)/142506

Pr(2 defective) = 0.11

P(at most 2 defective) = 0.46 + 0.42 + 0.11

P(at most 2 defective) = 0.99

3) Probability that at least one bulb is defective = Pr(1 defective) +  Pr(2 defective) +  Pr(3 defective) +  Pr(4 defective)

Pr(1 defective) =0.42

Pr(2 defective) = 0.11

Pr(3 defective) =  \frac{26C2  * 4C3}{30C5}

Pr(3 defective) = 0.009

Pr(4 defective) =  \frac{26C1  * 4C4}{30C5}

Pr(4 defective) = 0.00018

Pr(at least 1 defective) = 0.42 + 0.11 + 0.009 + 0.00018

Pr(at least 1 defective) = 0.54

3 0
3 years ago
How much longer is a pencil than a glue stick
balu736 [363]

depending on the size of both i would say 3 inches

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Help me please and thank you
Scorpion4ik [409]

Answer:

x = 20

y = 10

m∡8 = 110°

Step-by-step explanation:

m∡1 + m∡2 = 180

5x + y + 3x + y = 180

8x + 2y = 180

m∡1 = m∡8    (they are alternate-exterior angles and are congruent)

5x + y = 3x + 5y

2x = 4y

x = 2y

Substitute '2y' for 'x' in 8x + 2y = 180

8(2y) + 2y = 180

18y = 180

y = 10

x = 2(10)

x = 20

m∡8 = 3(20) + 5(10) = 110°

8 0
3 years ago
GIVING BRAINLIEST
bearhunter [10]

Heyo!

l believe the answer is D.

hopefully, this helps you!!!

idqfxemo~

6 0
1 year ago
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