All categories

3 years ago

Rationalise the denominator of 5√7 / √5

Mathematics

1 answer:

Tomtit [17]3 years ago

6 0

<h2>Question </h2>

Rationalize the denominator of 5√7/ √5

<h2>Answer </h2>

5√7 / √5

=> 5√7/√5×√5/√5

=> 5√7×5/(√5)^2

=> 5√35/5

=>√35

=> 5√7

<h2>So, the required answer is 5√7 . </h2>

You might be interested in

McGwire Aerospace expects to have net cash flow of $12 million. The company forecasts that its operating costs excluding depreci

slava [35]

Based on the net cash flow, the depreciation and amortization, and the tax rate, the expected sales of McGwire Aerospace is $66.67 million.

<h3>What are the expected sales?</h3>

First, find the net income:

= Net cash flow - depreciation and amortization

= 12 - 5

= 7 million

Given this net income, the sales are:

Net income = ( Sales - (Sales x 75%) - 5) x (1 - 40%)

7 / 0.60 = 0.25x - 5

11.67 = 0.25x - 5

0.25x = 16.67

x = 66.67 million

In conclusion, the expected sales are $66.67 million.

Find out more on expected sales at brainly.com/question/28062273

#SPJ4

7 0

1 year ago

Ten times the quotient of 104 and 8

GREYUIT [131]

104 ÷ 8 = 13
13 x 10 = 130
Answer: 130

If you need information about the quotient, it is the answer to 2 numbers divided together. For example, the quotient of 999 and 111 is 9, because 999 ÷111 =9

5 0

3 years ago

Read 2 more answers

Given the position of the particle, what the position(s) of the particle when it’s at rest

choli [55]

The position function of a particle is given by:

$X\mleft(t\mright)=\frac{2}{3}t^3-\frac{9}{2}t^2-18t$

The velocity function is the derivative of the position:

$\begin{gathered} V(t)=\frac{2}{3}(3t^2)-\frac{9}{2}(2t)-18 \\ \text{Simplifying:} \\ V(t)=2t^2-9t-18 \end{gathered}$

The particle will be at rest when the velocity is 0, thus we solve the equation:

$2t^2-9t-18=0$

The coefficients of this equation are: a = 2, b = -9, c = -18

Solve by using the formula:

$t=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}$

Substituting:

$\begin{gathered} t=\frac{9\pm\sqrt[]{81-4(2)(-18)}}{2(2)} \\ t=\frac{9\pm\sqrt[]{81+144}}{4} \\ t=\frac{9\pm\sqrt[]{225}}{4} \\ t=\frac{9\pm15}{4} \end{gathered}$

We have two possible answers: