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3 years ago

10

Hi! i’m really confused, so if anyone could help me.. that would be nice!

1 answer:

marusya05 [52]3 years ago

3 0

Answer:

I beleave that it is 12 because it look like for every 1 unit to the right it goes up 12.

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½x + 1 ⅔ subtracted from 1 ½x - 1 ⅓<br> simplify IF NEEDED!!

beks73 [17]

Answer:

x-3

Step-by-step explanation:

8 0

3 years ago

If 0.05x=20 then x=

Naya [18.7K]

0.05x=20
-------- -------
0.05 0.05

×=400

4 0

3 years ago

Read 2 more answers

A jet travels 460 miles in 2 hours. Atb this rate , how far could the jet fly in 11 hours? What is the rate of speed of the jet

USPshnik [31]

Answer:

230 MPH

2530 Miles

460miles/2 hours= 230 mph

230x11= 2530

5 0

3 years ago

How do I graph and find slope intercept for for x+y=0

lubasha [3.4K]

Answer:

y = -x + <u>0</u>

slope intercept: 0

Step-by-step explanation:

You would start at the origin, since your slope intercept is 0. The slope, -1 (since -x is the same as -1x), is telling us the line will be negative, so the line you are graphing will be heading up one space at a time towards the left, up 1 and sideways 1. Rise over Run.

4 0

3 years ago

Activity 2. Find the equation of the line using Two-Point form,

jasenka [17]

Answer:

1) equation of line is: y-3=0

2) equation of line is: $\mathbf{y-3=-\frac{1}{2}(x-4)}$

3) equation of line is: $\mathbf{y+3=-\frac{4}{3}(x-3}$

4) equation of line is: $\mathbf{y-2=-2(x-2)}$

Step-by-step explanation:

We need to find the equation of the line using Two-Point form.

The general equation of two-point form is: $y-y_1=m(x-x_1)$ where m is slope.

The formula used to calculate slope is: $Slope=\frac{y_2-y_1}{x_2-x_1}$

1. (1,3) and (-2,3)

First finding slope

We have: $x_1=1, y_1=3, x_2=-2, y_2=3$

$Slope=\frac{y_2-y_1}{x_2-x_1}\\Slope=\frac{3-3}{-2-1}\\Slope=\frac{0}{-3}\\Slope=0\\$

So, equation of line will be:

Using slope m=0 and point (1,3)

$y-y_1=m(x-x_1)\\y-3=0(x-1)\\y-3=0\\$

So, equation of line is: y-3=0

2. (4,3) and (6,2)

First finding slope

We have: $x_1=4, y_1=3, x_2=6, y_2=2$

$Slope=\frac{y_2-y_1}{x_2-x_1}\\Slope=\frac{2-3}{6-4}\\Slope=\frac{-1}{2}\\$

So, equation of line will be:

Using slope m= $\frac{-1}{2}$ and point (4,3)

$y-y_1=m(x-x_1)\\y-3=\frac{-1}{2}(x-4)\\y-3=-\frac{1}{2}(x-4)$

So, equation of line is: $\mathbf{y-3=-\frac{1}{2}(x-4)}$

3) (3,-3) and (0,1)

First finding slope

We have: $x_1=3, y_1=-3, x_2=0, y_2=1$

$Slope=\frac{y_2-y_1}{x_2-x_1}\\Slope=\frac{1-(-3)}{0-3}\\Slope=\frac{1+3}{-3}\\Slope=-\frac{4}{3}\\$

So, equation of line will be:

Using slope m= $-\frac{4}{3}$ and point (3,-3)

$y-y_1=m(x-x_1)\\y-(-3)=-\frac{4}{3}(x-3)\\y+3=-\frac{4}{3}(x-3)\\$

So, equation of line is: $\mathbf{y+3=-\frac{4}{3}(x-3)}$

4) (2,2) and (4,-2)

First finding slope

We have: $x_1=2, y_1=2, x_2=4, y_2=-2$

$Slope=\frac{y_2-y_1}{x_2-x_1}\\Slope=\frac{-2-2}{4-2}\\Slope=\frac{-4}{2}\\Slope=-2\\$

So, equation of line will be:

Using slope m=-2 and point (2,2)

$y-y_1=-2(x-x_1)\\y-2=-2(x-2)\\$

So, equation of line is: $\mathbf{y-2=-2(x-2)}$

3 0

3 years ago