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sammy [17]
3 years ago
10

Find the x intercepts of f(x) = –16x^2 + 22x + 3

Mathematics
1 answer:
Helga [31]3 years ago
4 0
That is where the line crosses the x axis or where y=0

0=-16x^2+22x+3
we gon do grouping
ac method
-16 times 3=-48

what 2 numbers multiply to get -48 and add to get 22
-2 and 24
0=-16x^2-2x+24x+3
group
0=(-16x^2-2x)+(24x+3)
undistribute
0=-2x(8x+1)+3(8x+1)
undistribute
0=(8x+1)(-2x+3)
set eaqual to 0

8x+1=0
8x=-1
x=-1/8

-2x+3=0
3=2x
3/2=x

x intercepts ate x=-1/8 and x=3/2
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