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hammer [34]
3 years ago
9

The actual cost of direct materials is $10.50 per pound. The standard cost per pound is $11.75. 42) During the current period 10

,000 pounds were used in production and 11,500 pounds werepurchased. The standard quantity for actual units produced is 9,900 pounds. The direct materials efficiency variance is:A) $1,175 favorable
B) $16,800 unfavorable
C) $1,175 unfavorable
D) $1,050 favorable
Business
1 answer:
emmainna [20.7K]3 years ago
3 0

Answer:

Direct materials efficiency variance =  1175 unfavorable

so correct option is C) $1,175 unfavorable

Explanation:

given data

actual cost = $10.50 per pound

standard cost per pound =  $11.75

current period  = 10,000 pounds

purchased = 11,500 pounds

actual units produced = 9,900 pounds

to find out

direct materials efficiency variance

solution

we get here Direct materials efficiency variance that is express as

Direct materials efficiency variance = Standard rate × ( Standard quantity - Actual quantity )     ..................1

put here value in equation 1 and  we get

Direct materials efficiency variance =  11.75 × ( 10000 - 9900 )

Direct materials efficiency variance = 11.75 × 100

Direct materials efficiency variance =  1175 unfavorable

so correct option is C) $1,175 unfavorable

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Answer:

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Bill O’Brien would like to take his wife, Mary, on a trip three years from now to Europe to celebrate their 40th anniversary. He
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Answer:

10%

Explanation:

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Future Value =  Present Value ((1+r)^n)

26,600 =  20,000 ((1+r)^3

26,600/20,000 = (1+r)^3

1.33 = (1+r)^3

1.33^1/3 = 1+r

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When a business sells more than one product at varying selling prices, the business's break-even point can be determined as long
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Answer: c. there is no limit

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6 0
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Read 2 more answers
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Answer:

Number 2 or Number 4.

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Fifteen families live in Willow Canyon. Although several water wells have been drilled, none hasproduced water. The residents ta
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Answer:

Initial Investment, P = $100, 000

Recurring Cost, A=$6200

(a)  Calculate the internal rate of return for infinite life,

A= P(i)

6200=100000(i)

i = 6200/100000  

i =6.2%

(b)  Calculate the internal rate of return for 100 years,

P = A(P/A, i, 100)

100000 = 6200 (P/A, i, 100)

(P/A, i, 100) = 16.129

For i = 6%

(P/A,6%,100) = 16.618

For i = 7%

(P/A ,7%,100) = 14.269

i = [(6 - 7) / (16.618 - 14.269)] (16.129 - 16.618) +6

i = 6.2%

Thus, IRR = 6.2%

(c) Calculate the internal rate of return for 50 years,

P = A(P/A ,i , 50)

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For i = 6%

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i = 5.853%

Thus, IRR = 5.853%

(d)  

In all cases internal rate of return is greater than 4%, which is minimum interest rate that one can earn. So they should consider to install the pipeline.

6 0
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