The feeders in battling machine are represented in proportions and fractions.
- The equation that represents the problem is:
- The feeder can hold <em>30 baseballs</em>, when full
The given parameters are:
<em />
<em> ------ 1/6 full</em>
<em />
<em> --- baseballs added</em>
<em />
<em> ---- 2/3 full</em>
<em />
So, the equation that represents the problem is:
So, we have:
The number of baseballs it can hold is calculated as follows:
Multiply through by 6
Collect like terms
Divide through by 3
Hence, the feeder can hold 30 baseballs, when full
Read more about proportions and fractions at:
brainly.com/question/20337104
Answer:
- EF = 4.1
- DE = 9.1
- m∠F = 66°
Step-by-step explanation:
The hypotenuse and one acute angle are given. The relevant relations are ...
Sin = Opposite/Hypotenuse
Cos = Adjacent/Hypotenuse
__
For the given triangle, these tell us ...
sin(24°) = EF/DF = EF/10
EF = 10·sin(24°) ≈ 4.1
and ...
cos(24°) = DE/DF = DE/10
DE = 10·cos(24°) ≈ 9.1
The remaining acute angle is the complement of the given one:
F = 90° -D = 90° -24°
∠F = 66°
The triangle was just flipped so the missing side is going to equal 36, so...
2y+20= 36
(Subtract 20 from each side to isolate the 2y)
2y= 16
(Divide each side by 2 to isolate the variable)
ANSWER:
y= 8
