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AnnyKZ [126]
3 years ago
14

Determine which two equations have nonlinear graphs.

Mathematics
1 answer:
vodomira [7]3 years ago
3 0

The slope-intercept form of linear function:

y=mx+b

y=2x^3 - nonlinear

y=3x - linear

y=2x+\dfrac{1}{2} - linear

y=x^2+2 - nonlinear

y=0.5x+3 - linear

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1. How many squares will it take<br> to cover the figure below?
Ne4ueva [31]

Answer:

Unable to tell you

Step-by-step explanation:

Due to the fact we can't see the shape below, we are unable to help you. make sure to post a picture next time!

8 0
4 years ago
How does the graph of g(x)= 2^x+3differ from the graph of f(x) = 2^xАIt is moved up 3 unitsBIt is moved down 3 unitsCIt is moved
Readme [11.4K]
\begin{gathered} g(x)=2^{x+3} \\ f(x)=2^x \end{gathered}

4 0
1 year ago
a rectangle has sides that are 23 m 19 m and 19 m what is a rectangles lengthA. 19 mB. 23 mC. 84 mD. 46 mthis is what it said Th
sdas [7]

Given Data:

The sides of the rectangle are 23 m, 23 m ,19 m and 19 m.

The length of the rectangle is 23 m.

Thus, option (B) is the correct option.

4 0
1 year ago
Does the table represent a exponential function x 1 2 3 4 y -1 -8 -27 -64
Setler79 [48]

Answer:

No, the given function is not an exponential function.

Step-by-step explanation:

The exponential function is defined as

f(x)=ab^x                   .... (1)

Where a is initial value and b is growth factor.

From the given table it is noticed that the value of y decreased as the value of x increased by 1. The function is in the form of

f(x)=-x^3                  .... (2)

f(1)=-(1)^3=-1

f(2)=-(2)^3=-8

f(3)=-(3)^3=-27

f(4)=-(4)^3=-64

The function (1) and (2) are not the same type of function.

The table represents the polynomial.

Therefore the required answer is no. The given function is not an exponential function.

8 0
3 years ago
Which number would make the sentence true?
AURORKA [14]

Answer:

22% = 0.22

Step-by-step explanation:

Lat'e express all the given numbers in decimal form so we understand how they are located on the number line.

We start with 2/11 , since the number we are looking for has to be larger than this \, and smaller than 1.42:

\frac{2}{11} = 0.181818181818...

So we understand that we are looking for a number that can be placed between the lower boundary (0.181818...) and the upper boundary (1.42) on the number line. That is: we are looking for a number greater than 0.18181818... and less than 1.42.

Now let's look at each of the given options (also writing them in decimal form to facilitate the comparison with the lower and upper boundaries we just found):

1\frac{2}{3} = 1.66666666... This number is grater than the upper boundary given to us (1.42), it would be placed to the right of 1.42 on the number line. Therefore we discard it for not being in the requested interval (section) of the number line.

0.153 is already in decimal form, and clearly less than (thus to be placed on the left of) the lower boundary (0.181818...) of the requested interval. Therefore we discard it for not being in the requested interval (section) of the number line.

22% in decimal form is written as: \frac{22}{100} = 0.22. This number is greater than the lower boundary (0.181818...) and also less than the upper boundary (1.42). Therefore it is a choice that would make the sentence true.

1.3*10^1=1.3*10=13 which is clearly greater than the upper boundary of the interval, so we discard it.

7 0
3 years ago
Read 2 more answers
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