What is the solution set for 3x+1≥8 and 10x≤15

If h and j are positive, (h+j)2 = 73 and h2 +j2 = 51, what is hj?

kkurt [141]

Answer:

$hj = 11$

Step-by-step explanation:

$(h+j)^2=73,\:\: and\:\: h^2+j^2 =51$ (Given)

$(h+j)^2 = h^2+j^2 +2hj$

$\implies 73= 51 +2hj$

$\implies 73- 51 =2hj$

$\implies 22 =2hj$

$\implies hj = \frac{22}{2}$

$\implies hj = 11$

3 0

2 years ago

What is a correct congruence statement for the triangles shown? Enter your answer in the box. △QDJ≅△ A triangle Q D J. The b

almond37 [142]

Answer: The correct congruence statement is $\triangle QDJ\cong \triangle MCW$ .

Explanation:

It is given that A triangle Q D J. The base D J is horizontal and side Q D is vertical. Another triangle M C W is made. The base C W and side M C are neither horizontal nor vertical. Triangle M C W is to the right of triangle Q D J.

The sides Q D and M C are labeled with a single tick mark. The sides D J and C W are labeled with a double tick mark. The sides Q J and M W are labeled with a triple tick mark.

Draw two triangles according to the given information.

From the figure it is noticed that

$QD\cong MC$

$DJ\cong CW$

$QJ\cong MW$

So by SSS rule of congruence we can say that $\triangle QDJ\cong \triangle MCW$ .

4 0

2 years ago

Read 2 more answers

Label the missing side lenght of the figure khan academy

hammer [34]

Answer:

i cant telll bc theres no picture

3 0

2 years ago

Using a number cube and this hat with 5 different-colored marbles, which simulation would help you answer this question? During

Arlecino [84]

Answer:

see the attachment

Step-by-step explanation:

We assume that the question is interested in the probability that a randomly chosen class is a Friday class with a lab experiment (2/15). That is somewhat different from the probability that a lab experiment is conducted on a Friday (2/3).

Based on our assumption, we want to create a simulation that includes a 1/5 chance of the day being a Friday, along with a 2/3 chance that the class has a lab experiment on whatever day it is.

That simulation can consist of choosing 1 of 5 differently-colored marbles, and rolling a 6-sided die with 2/3 of the numbers being designated as representing a lab-experiment day. (The marble must be replaced and the marbles stirred for the next trial.) For our purpose, we can designate the yellow marble as "Friday", and numbers greater than 2 as "lab-experiment".

The simulation of 70 different choices of a random class is shown in the attachment.

_____

Comment on the question

IMO, the use of 70 trials is coincidentally the same number as the first 70 days of school. The calendar is deterministic, so there will be exactly 14 Fridays in that period. If, in 70 draws, you get 16 yellow marbles, you cannot say, "the probability of a Friday is 16/70." You need to be very careful to properly state the question you're trying to answer.