Answer:
There are 0.005 hundreds in 5/10.
Step-by-step explanation:
Claire drew model of 5/10
We want to know how many hundreds are in 5/10.
Let us use an obvious example.
There are three 2's in 6 right?
Suppose we didn't know this, and we are told to find how many 2's are in 6, we get this by representing this in an algebraic expression as:
There are x 2's in 6. This can be written as
2x = 6
Solving for x, by dividing both sides by 2, we have the number of 2's that are in 6.
x = 6/2 = 3.
Now, to our work
We want to find how many hundreds are in 5/10. We solve the equation
100x = 5/10
x = 5/1000 = 0.005
There are 0.005 hundreds in 5/10.
Have you never added 2-digit numbers?
35 +27 = (30 +20) +(5 +7) = 50 +12 = 62
35/100 +27/100 = (35 +27)/100 = 62/100
0.35 +0.27 = 0.62
The basic idea, taught in 3rd grade, is to line up the decimal points of the numbers, add enough zeros on the right to make the numbers all have the same number of digits to the right of the decimal point, then add in the usual way. The sum has the decimal point aligned with the rest of the numbers.
A median intersects at the midpoint of the opposite length. The midpoint is:
x,m = (4+-2)/2 = 1
y,m = (-1+7)/2 = 3
The midpoint is at (1,3). With this point and point R(9,9), the equation would be:
y = mx + b, where
m = (9 - 3)/(9 - 1) = 0.75
b is the y-intercept
Substituting any point,
3 = 0.75(1)+b
b = 2.25
Thus, the equation for the median is:
y = 0.75x + 2.25
I think the answer is D. If I’m wrong sorry