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liubo4ka [24]
3 years ago
7

Math help? One question?

Mathematics
1 answer:
Lera25 [3.4K]3 years ago
3 0
My triangle solver says EF ≈ 7.5 ft.

_____
The law of cosines is usually used for this.

EF^2 = DE^2 +DF^2 -2*DE*DF*cos(D)
.. = 6^2 +11^2 -2*6*11*cos(40°)
.. ≈ 55.88

EF ≈ √55.88 ≈ 7.5 . . . ft

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Emily has 140 books. If Frank were to triple the number of books that he now owns, he would still have fewer than Emily has.
aniked [119]
B * 3 < 140
B being the number of books Frank owns. Because tripling the amount of books he owns is still less than the amount of book Emily owns, b*3 has to be less than 140
3 0
3 years ago
Read 2 more answers
PLZ HELP ASAP! WILL MARK BRAINLIEST!!
stepan [7]

Answer:

I believe this is right.  Answer: 6/7

Step-by-step explanation:

5+1 = 6

The denominator stays the same.

6 0
3 years ago
Amuseumcharges forgeneraladmission and exhibitions. Admission and 3 exhibitionscosts $45. Admission and 5 exhibitionscosts $65.
leonid [27]

Answer:

The price of the admission is 15.

Step-by-step explanation:

From the information given, you can write the following equations:

a+3e=45 (1)

a+5e=65 (2), where:

a is the admission cost

e is the exhibition cost

First, you can solve for a in (1):

a=45-3e (3)

Second, you can replace (3) in (2):

45-3e+5e=65

45+2e=65

2e=65-45

2e=20

e=20/2

e=10

Finally, you can replace the value of e in (3):

a=45-3e

a=45-3(10)

a=45-30

a=15

According to this, the price of the admission is 15.

3 0
3 years ago
Evaluate each expression if m = 3, n = 7, and p = 9
katrin2010 [14]

Answer:

27

Step-by-step explanation:

<u><em>First, you would do 7+2 to get 9 and then multiply it by itself to get 81. Next, you divide 81 by 3 to get 27.</em></u>

4 0
3 years ago
Read 2 more answers
The equation a=1/2(b^1+b^2)h can be determined the area, a, of a trapezoid with height, h, and base lengths, b^1 and b^2 Which a
Evgesh-ka [11]

The complete question is as follows.

The equation a = \frac{1}{2}(b_1 + b_2 )h can be used to determine the area , <em>a</em>, of a trapezoid with height , h, and base lengths, b_1 and b_2. Which are equivalent equations?

(a) \frac{2a}{h} - b_2 = b_1

(b) \frac{a}{2h} - b_2 = b_1

(c) \frac{2a - b_2}{h} = b_1

(d) \frac{2a}{b_1 + b_2} = h

(e) \frac{a}{2(b_1 + b_2)} = h

Answer: (a) \frac{2a}{h} - b_2 = b_1; (d) \frac{2a}{b_1 + b_2} = h;

Step-by-step explanation: To determine b_1:

a = \frac{1}{2}(b_1 + b_2 )h

2a = (b_1 + b_2)h

\frac{2a}{h} = b_1 + b_2

\frac{2a}{h} - b_2 = b_1

To determine h:

a = \frac{1}{2}(b_1 + b_2 )h

2a = (b_1 + b_2)h

\frac{2a}{(b_1 + b_2)} = h

To determine b_2

a = \frac{1}{2}(b_1 + b_2 )h

2a = (b_1 + b_2)h

\frac{2a}{h} = (b_1 + b_2)

\frac{2a}{h} - b_1 = b_2

Checking the alternatives, you have that \frac{2a}{h} - b_2 = b_1 and \frac{2a}{(b_1 + b_2)} = h, so alternatives <u>A</u> and <u>D</u> are correct.

4 0
3 years ago
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