All categories

3 years ago

I've been stuck on this question for 3 days ;< halp meh ples

Mathematics

1 answer:

zimovet [89]3 years ago

4 0

Answer:

avg time = total time/ 3

for big car :-

= 4.46/ 3

= 1.48

for small car :-

= 5.14/ 3

= 1.71

avg speed = total distance/ total time

for big car:-

= 2/ 4.46

= 0.45

for small car :-

= 2/ 5.14

= 0.4

You might be interested in

The students in Ms. Hill’s class are reading a 325-page book. There are about 90,000 words in the book.

NeX [460]

Answer:

225

Step-by-step explanation:

(90000÷325)×65=18000

18000÷80=225

reading rate of 225 words per minutes

5 0

3 years ago

Why is it important to include the units in a rate

bija089 [108]

Answer:

Unit rates are useful because they allow you to make direct comparisons. For example, you have your choice between two bottles of ketchup.

Step-by-step explanation:

7 0

4 years ago

What is the width of it

notka56 [123]

The width of the rectangle is 16cm. this is because 16x4 = 64. so the height of the rectangle is 64 cm and 16cmx64cm = 1024cm squared. which is why the width of the rectangle is 16cm.

4 0

3 years ago

In the following calculation, which part should be calculated first? 3 + (2 * 4) - 5 / 2

meriva

Always solve the parenthese first

8 0

3 years ago

Read 2 more answers

The probability that an American CEO can transact business in a foreign language is .20. Twelve American CEOs are chosen at rand

NNADVOKAT [17]

Answer with Step-by-step explanation:

We are given that

The probability that an American CEO can transact business in foreign language=0.20

The probability than an American CEO can not transact business in foreign language= $1-0.20=0.80$

Total number of American CEOs chosen=12

a. The probability that none can transact business in a foreign language= $12C_0(0.20)^0(0.80)^{12}$

Using binomial theorem $nC_r(1-p)^{n-r}p^r$

The probability that none can transact business in a foreign language= $\frac{12!}{0!(12-0)!}(0.8)^{12}=(0.8)^{12}$

b.The probability that at least two can transact business in a foreign language= $1-P(x=0)-p(x=1)=1-((0.8)^{12}+12C_1(0.8)^{11}(0.2))=1-((0.8)^{12}+12(0.8)^{11}}(0.2))$

c.The probability that all 12 can transact business in a foreign language= $12C_{12}(0.8)^0(0.2)^{12}$

The probability that all 12 can transact business in a foreign language= $\frac{12!}{12!}(0.2)^{12}=(0.2)^{12}$

5 0

3 years ago