Find four consecutive even integers whose sum is 60
1 answer:
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Hey there, hope I can help!
Assuming you know how to simplify this, I will not show the steps but can add them later on upon request
Lets use the quadratic formula now
Multiply the numbers 2 * 1 = 2
![\mathrm{Apply\:radical\:rule}: \sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b} \ \textgreater \ \sqrt{47}\sqrt{2^2}](https://tex.z-dn.net/?f=%5Cmathrm%7BApply%5C%3Aradical%5C%3Arule%7D%3A%20%5Csqrt%5Bn%5D%7Bab%7D%3D%5Csqrt%5Bn%5D%7Ba%7D%5Csqrt%5Bn%5D%7Bb%7D%20%5C%20%5Ctextgreater%20%5C%20%20%5Csqrt%7B47%7D%5Csqrt%7B2%5E2%7D%20)
![\mathrm{Apply\:radical\:rule}: \sqrt[n]{a^n}=a \ \textgreater \ \sqrt{2^2}=2 \ \textgreater \ 2\sqrt{47} \ \textgreater \ \frac{2+2\sqrt{47}}{2}](https://tex.z-dn.net/?f=%5Cmathrm%7BApply%5C%3Aradical%5C%3Arule%7D%3A%20%5Csqrt%5Bn%5D%7Ba%5En%7D%3Da%20%5C%20%5Ctextgreater%20%5C%20%20%5Csqrt%7B2%5E2%7D%3D2%20%5C%20%5Ctextgreater%20%5C%20%202%5Csqrt%7B47%7D%20%5C%20%5Ctextgreater%20%5C%20%20%5Cfrac%7B2%2B2%5Csqrt%7B47%7D%7D%7B2%7D)
Moving on, I will do the second part excluding the extra details that I had shown previously as from the first portion of the quadratic you can easily see what to do for the second part.
Therefore our final solutions are
Hope this helps!
Assuming you know how to simplify this, I will not show the steps but can add them later on upon request
Lets use the quadratic formula now
Multiply the numbers 2 * 1 = 2
Moving on, I will do the second part excluding the extra details that I had shown previously as from the first portion of the quadratic you can easily see what to do for the second part.
Therefore our final solutions are
Hope this helps!
The answer is either or
To solve: Let's solve your equation step-by-step.
5x2+5x−x2−x=2004
Step 1: Simplify both sides of the equation.
4x2+4x=2004
Step 2: Subtract 2004 from both sides.
4x2+4x−2004=2004−2004
4x2+4x−2004=0
Step 3: Use quadratic formula with a=4, b=4, c=-2004.
x= −b±√b2−4ac /2a
x= −4±√32080 /8
or