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zvonat [6]
3 years ago
11

On a certain hot​ summer's day, 500 people used the public swimming pool. The daily prices are $1.50 for children and $2.25 for

adults. The receipts for admission totaled $942.75. How many children and how many adults swam at the public pool that​ day?
Mathematics
1 answer:
Anvisha [2.4K]3 years ago
5 0

Answer:

IIG&UI*^&TG763eh783hiubydhe8743h^%ti289d3r8hf4y9h39857ty58i5

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Is the answer infinite, zero, or indefinite <br> 2x - 1 = 1 - 2x
RUDIKE [14]

Answer: 1/2 indefinite

Step-by-step explanation:

8 0
4 years ago
Find the intercepts and the vertical and horizontal asymptotes, and then use them to sketch a graph of the function. f(x)=x+2/x^
hoa [83]

We have the function:

f(x)=x+\frac{2}{x^2}-16.

We must find:

0. the intercepts,

,

1. the vertical and horizontal asymptotes.

1) x-intercepts

The x-intercepts are given by the x values such that f(x) = 0. So we must find the values of x that satisfies the equation:

f(x)=x+\frac{2}{x^2}-16=0.

Solving for x, we get:

\begin{gathered} x+\frac{2}{x^2}-16=0 \\ x\cdot x^2+2-16\cdot x^2,\text{ }x\ne0, \\ x^3-16x^2+2=0. \end{gathered}

The real roots of this equation are:

\begin{gathered} x_1\approx15.9922, \\ x_2\approx0.35757, \\ x_3\approx-0.34975. \end{gathered}

So the x-intercepts are the points:

\begin{gathered} P_1=(15.9922,0), \\ P_2=(0.35757,0), \\ P_3=(-0.34975,0)\text{.} \end{gathered}

2) y-intercepts

The y-intercepts are given by the y values such that x = 0. Replacing x = 0 in the definition f(x), we see that the denominator of the second term diverges. So we conclude that there are no y-intercepts.

3) Vertical asymptotes

Vertical asymptotes are vertical lines near which the function grows without bound. From point 2, we know that the function grows without limit when x goes to zero. So one vertical asymptote is:

x=0.

4) Horizontal asymptotes

Horizontal asymptotes are horizontal lines that the graph of the function approaches when x → ±∞. We consider the limit of the function f(x) when x → ±∞:

\lim _{x\rightarrow\pm\infty}f(x)=\lim _{x\rightarrow\pm\infty}(x+\frac{2}{x^2}-16)\rightarrow\pm\infty.

We see that the function does not tend to any constant value when x → ±∞. So we conclude that there are no horizontal asymptotes.

5) Oblique asymptotes

When a linear asymptote is not parallel to the x- or y-axis, it is called an oblique asymptote or slant asymptote.

A function ƒ(x) is asymptotic to the straight line y = mx + n (m ≠ 0) if

{\displaystyle\lim _{x\to+\infty}\mleft[f(x)-(mx+n)\mright]=0\, {\mbox{ or }}\lim _{x\to-\infty}\mleft[f(x)-(mx+n)\mright]=0.}

We consider the line given by:

y=mx+n=x-16.

We compute the limit:

\begin{gathered} \lim _{x\rightarrow\pm\infty}(f(x)-(x-16)) \\ =\lim _{x\rightarrow\pm\infty}((x+\frac{2}{x^2}-16)-(x-16)) \\ =\lim _{x\rightarrow\pm\infty}(\frac{2}{x^2}) \\ =0. \end{gathered}

So we have proven that f(x) has the oblique asymptote:

y=x-16.

6) Graph

Plotting the intercepts and the asymptotes, we get the following graph:

Answer

1) x-intercepts: (-0.34975, 0), (0.35757, 0), (15.9922, 0)

2) y-intercepts: none

3) Vertical asymptotes: x = 0

4) Horizontal asymptotes: none

5) Oblique asympsotes: y = x -16

6) Graph

6 0
1 year ago
A triangle has vertices on a coordinate grid at P(-10,1)P(−10,1), Q(-10,-7)Q(−10,−7), and R(-5,-7).R(−5,−7). What is the length,
lys-0071 [83]

Answer:

Step-by-step explanation:

Given the following coordinates of a triangle

P(-10,1)

Q(-10,-7)

R(-5,-7)

Required

Length of PQ

PQ = √(y2-y1)²+(x2-x1)²

From the coordinate;

x1 = -10, y1 = 1, x2 = -10 y2 = -7

Substitute

PQ = √(-7-1)²+(-10-(-10))²

PQ = √(-8)²+0²

PQ = √64

PQ = 8units

Hence the length of PQ in units is 8units

3 0
3 years ago
4 more than the quotient of -3 and a number n is 12
serg [7]

Answer:

(-3/n)+4=12

Hope this helps

4 0
3 years ago
Aaron has 5 dimes and 2 nickels. how much money does Aaron have?
Doss [256]

Knowing that one dime has a 10 cent value and that a nickle has a 5 cent value, we can use multiplication or addition to find the answer.

5 x 10 = 50   5 dimes together are worth 50 cents.

2 x 5 = 10  2 nickles together are worth 10 cents.

50 + 10 = 60   5 dimes and 2 nickles are worth 60 cents when added together.

ANSWER: Aaron has 60 cents.

7 0
4 years ago
Read 2 more answers
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