All categories

3 years ago

You measure the width of a doorway and find that it is 1.1 m wide. Find the greatest possible error of your measurement.

Mathematics

2 answers:

IRINA_888 [86]3 years ago

7 0

Answer:

Option B- 0.05 m

Step-by-step explanation:

Given : Width of a doorway is 1.1 m wide.

To find : The greatest possible error of your measurement.

Solution :

The GPE - Greatest possible error in a measurement is half of the precision.

So, To find the GPE of 1.1 m

First we look that it is in decimal form so place value of last number.

In 1.1 place value of 1 (after decimal) is tenth place.

So, The precision is 0.1

GPE = Half of the precision

$GPE=\frac{0.1}{2}=0.05$

Therefore, The greatest possible error of 1.1 m width is 0.05 m.

So, Option B is correct.

Mama L [17]3 years ago

5 0

Answer: Hello!

If the measure found is 1.1 m, means that the smallest "graduation" of your ruler (the precision of the ruler) is for 0.1m

Then, with this ruler, you only can differ between the values of 1.1 m and 1.2m

But you also could measure just in between, if the end of the dorway is rigth in between the values of 1.1m and 1.2m, the point 1.15m is a good meassure.

So the actual smaller possible measure is 0.05m, which means that the greatest possible error is 0.05m

So the right answer is the second option.

You might be interested in

What is the y intercept of a line that passes through (1,-7) and (5,-25). How do I find it.

LUCKY_DIMON [66]

Answer:

y- intercept = - 2.5

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

with (x₁, y₁ ) = (1, - 7) and (x₂, y₂ ) = (5, - 25)

m = $\frac{-25+7}{5-1}$ = $\frac{-18}{4}$ = - 4.5 , then

y = - 4.5x + c

To find c substitute either of the 2 points into the equation

Using (1, - 7), then

- 7 = - 4.5 + c ⇒ c = - 7 + 4.5 = - 2.5

y- intercept c = - 2.5

3 0

2 years ago

Need help with this refer to picture

aalyn [17]

First one C second one D sorry if I’m wrong

5 0

2 years ago

Read 2 more answers

PLEASE HELP NEED THIS ANSWERED CORRECTLY

Helen [10]

f(3) = 1.9

Solution:

Given function:

$$f(x)=\frac{14}{7+2 e^{-0.6 x}}$

To find f(3):

Substitute x = 3 in the given function.

$$f(3)=\frac{14}{7+2 e^{-0.6 (3)}}$

$$f(3)=\frac{14}{7+2 e^{-1.8}}$

Let us first simplify $2e^{-1.8}$ .

Apply exponent rule: $a^{-b}=\frac{1}{a^{b}}$

$2e^{-1.8}=2\frac{1}{e^{1.8}}$

The value of $e^{1.8}=6.04964$ . (using calculator)

$$\frac{2}{e^{1.8}}=\frac{2}{6.04964}=0.33059$

$2e^{-1.8}=0.33059$

Substitute this value in f(3).

$$f(3)=\frac{14}{7+0.33059}$

$$f(3)=\frac{14}{7.33059}$

$$f(3)=1.90980$

f(3) = 1.9

Hence the value of f(3) is 1.9.

3 0

3 years ago

The U.S. Census Bureau conducts a study to determine the time needed to complete the short form. The Bureau surveys 200 people.

NISA [10]

Answer:

$8.2-2.58\frac{2.2}{\sqrt{18}}=6.86$

$8.2+2.58\frac{2.2}{\sqrt{18}}=9.54$

So on this case the 90% confidence interval would be given by (6.86;9.54) And the error is given by:

$ME= 2.58\frac{2.2}{\sqrt{18}} =1.338$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=8.2$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

$\sigma=2.2$ represent the population standard deviation

n represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

Since the Confidence is 0.90 or 90%, the value of $\alpha=0.1$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.005,0,1)".And we see that $z_{\alpha/2}=2.58$