This is the number of combinations of 2 from 23
23C2 = 23! / 2! 21!
A quick way to do this is 23*22 / 2 = 253
Answer:
a=5, b=-2
Step-by-step explanation:
If you simplify the equation, you get:
3ax +6 -4x -4b - 11x - 14 = 0 =>
3ax - 15x -4b -8 = 0
group together x's and constants:
(3a-15)x -8 -4b = 0
To make this 0 for all x, we have to find an a such that 3a-15 = 0 and b such that -8-4b = 0. this leads to a=5, b=-2
Answer:
Step-by-step explanation:
Let's label this triangle as triangle ABC. Side AB is 18, side BC is 20 and side CA is 25 and the angle we are looking for is angle C. Use the Law of Cosines to find the missing angle. You have to use the Law of Cosines because in order to use the Law of Sines you have to have an angle given and we don't so we have no other options. In our case,
which for us looks like this:
and
and
and
and
Use the 2nd button and the cos button to find the missing angle.
Angle C = 45.4 which is, rounded to the nearest degree, 45°
Answer: Most likely, the value of w is 5 units.
Step-by-step explanation: P = 2L + 2w
If the perimeter is 28, the side lengths must be less than 14, otherwise there is no width, just two lines on top of one another.
If the width is 7, then all four sides would be 7 units, and <u>that would create a square</u>-- which is a type of rectangle-- but probably not what this question is about.
A width of 5 units makes sense, 2w would be 10, leaving 28-10 = 18 to be divided by 2 for lengths of 9
The rectangle would have a width of 5 units and a length of 9 units.
