Let the required number is 2x ,
According to the condition,
➡ 10 times the sum of half of 2x and 6 = 8

Therefore the value of x is -5.2
And, required number is -5.2
Answer:
2/7
Step-by-step explanation:
You do the number it goes up, 1 to 3 in this case, over the number it goes sideways, 3 to -4. My teacher always said rise over run to help us remember.
Answer:

Step-by-step explanation:
Comparing it with quadratic equation
, we get:
a = 1 . b = 4 and c = 5
So,
Discriminant = 
D = (4)²-4(1)(5)
D = 16 - 20
D = -4
Hence,
Discriminant = -4
![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3 /><h3>~AH1807</h3>
Answer: 343 in³
Explanation: In this problem, we're asked to find the volume of a cube.
It's important to understand that a cube is a type of rectangular prism and the formula for the volume of a rectangular prism is shown below.
<em>Volume = length × width × height</em>
In a cube however, the length, width, and height are all the same. So we can use the formula side × side × side instead.
So the formula for the volume of a cube is side × side × side or s³.
So to find the volume of the given cube, since each side has a length of 7 inches, we can plug this information into the formula to get (7 in.)³ or (7 in.)(7 in.)(7 in).
7 x 7 is 49 and 49 x 7 is 343.
So we have 343 in³.
So the volume of the given cube is 343 in³.
Answer:
The answer to this question would be B:
Based on the question, since the weight of the weight plates are 20 lbs, this would be represented by the 20x in the function. As well, the 5 lb barbell would be represented by the 5 in the function. The range of the function is determined by the amount of weight plates are added. So if I added one weight plate the equation would equal, f(x) = 20(1) + 5 = 25. This continues on the more and more weight plates you add.
Hope this reached you well :)
Step-by-step explanation:
20 = weight of the weight plates
x = amount of weight plates.
5 = weight of the barbell
f(x) = 20(0) + 5 = 5
f(x) = 20(1) + 5 = 25
f(x) = 20(2) + 5 = 45
f(x) = 20(3) + 5 = 65
f(x) = 20(4) + 5 = 85