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3 years ago

Solve the following equation for a number x. verify that your solution is correct 7(2x+5=4x-9-x

Mathematics

1 answer:

Kisachek [45]3 years ago

8 0

7(2x+5)=4x-9-x
14x+35=3x-9
11x = -44
x = -4

7(2*-4+5)=4*-4-9--4
7(-3)=-21
-21=-21. so it checks out and x = -4

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An amusement park offers two options. Option 1 involves a $10 admission fee plus $0.50 per ride. Option 2 involves a $6 admissio

Art [367]

Answer:

16 rides

Step-by-step explanation:

Option 1 . Admission fee = $10

Each ride = $0.50

Option 2 . Admission fee = $6

Each ride = $0.75

Let no. of rides be x

So, cost of ride according to option 1 = 0.50x

So, total cost after having x rides according to option 1 :

= 10+0.50x ---1

Cost of ride according to option 2 = 0.75x

So, total cost after having x rides according to option 2 :

= 6+0.75x --2

Now to find the beak even point i.e. having the same cost

Equate 1 and 2

$10+0.50x=6+ 0.75x$

$10-6= 0.75x-0.50x$

$4= 0.25x$

$\frac{4}{0.25} =x$

$16=x$

Thus for 16 rides , the two options have the same cost .

Hence the break even point is 16 rides

5 0

4 years ago

What is the determinant of k =[ 6 8]

Sergeeva-Olga [200]

That would be 6 *3 - 8*0 = 18

Its D

5 0

3 years ago

If the unit price of oranges is 0.08 per pound and Jim pays 2.08 how many oranges does he buy

kobusy [5.1K]

26 I believe, I'm pretty sure :)

3 0

3 years ago

ryan has a mix of action and sports games for a total of 39 video games his action collection is three more than half his sports

iVinArrow [24]

Answer:

He have 15 action games and 24 sports games.

Step-by-step explanation:

Given:

Ryan has a mix of action and sports games for a total of 39 video games his action collection is three more than half his sports collection.

Now, to find the number of action games and sports games.

Let the sports games be $x.$

As, given his action collection is three more than half his sports collection.

Thus, the action games = $3+\frac{x}{2}$ .

Total number of video games = 39.

So, we set an equation to get the number of action games and sports games:

$x+(3+\frac{x}{2})=39$

$x+3+\frac{x}{2} =39$

Subtracting both sides by 3 we get:

$x+\frac{x}{2} =36$

$\frac{2x+x}{2}=36$

$\frac{3x}{2} =36$

Multiplying both sides by 2 we get:

$3x=72$

Dividing both sides by 3 we get:

$x=24.$

The sports games he have = 24.

Now, to get the action games we substitute the value of $x$ :

$3+\frac{x}{2}$

= $3+\frac{24}{2}$

= $3+12$

= $15.$

The action games he have = 15.

Therefore, he have 15 action games and 24 sports games.

6 0

3 years ago

Estimate 195 divided by 4. Tell which method is used.

ki77a [65]

195 ÷ 4 = 48.75
Is this what you wanted?

4 0

3 years ago

Read 2 more answers