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neonofarm [45]
2 years ago
9

4(x+7)+3(2x-3) what is the answer to this

Mathematics
2 answers:
madam [21]2 years ago
8 0

Answer:

10x+19 i think

sergey [27]2 years ago
6 0

4(x+7)+3(2x-3)

mutiply the first bracket by 4

(4)(x)= 4x

(4)(7)= 28

mutiply the second bracket by 3

(3)(2x)= 6x

(3)(-3)= -9

4x+28+6x-9

4x+6x+28-9 ( combine like terms)

Answer:

10x+19 or 19+10x

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Given:

The expression is:

\dfrac{1-\cos 2x}{1+\cos 2x}

To find:

The integration of the given expression.

Solution:

We need to find the integration of \dfrac{1-\cos 2x}{1+\cos 2x}.

Let us consider,

I=\int \dfrac{1-\cos 2x}{1+\cos 2x}dx

I=\int \dfrac{2\sin^2x}{2\cos^2x}dx         [\because 1+\cos 2x=2\cos^2x,1-\cos 2x=2\sin^2x]

I=\int \dfrac{\sin^2x}{\cos^2x}dx

I=\int \tan^2xdx                      \left[\because \tan \theta =\dfrac{\sin \theta}{\cos \theta}\right]

It can be written as:

I=\int (\sec^2x-1)dx             [\because 1+\tan^2 \theta =\sec^2 \theta]

I=\int \sec^2xdx-\int 1dx

I=\tan x-x+C

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8 0
2 years ago
PLS HELP ME :(
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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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