4(x+7)+3(2x-3) what is the answer to this
2 answers:
4(x+7)+3(2x-3)
mutiply the first bracket by 4
(4)(x)= 4x
(4)(7)= 28
mutiply the second bracket by 3
(3)(2x)= 6x
(3)(-3)= -9
4x+28+6x-9
4x+6x+28-9 ( combine like terms)
Answer:
10x+19 or 19+10x
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Step-by-step explanation:
we have the number
![6-\sqrt[]{-40}](https://tex.z-dn.net/?f=6-%5Csqrt%5B%5D%7B-40%7D)
Remember that
i^2=-1
so
substitute
![6-\sqrt[]{(i^2)40}](https://tex.z-dn.net/?f=6-%5Csqrt%5B%5D%7B%28i%5E2%2940%7D)
![6-2i\sqrt[]{10}](https://tex.z-dn.net/?f=6-2i%5Csqrt%5B%5D%7B10%7D)
therefore
the real part is 6
the imaginary part is -2√10
Answer:
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Step-by-step explanation:
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