The reaction force exerted by the floor of the elevator on the man is D.944 N
Step-by-step explanation:
When the elevator is accelerating upwards at 2 m/s² there occurs a fictitious force acting downwards to produce a downward acceleration of 2 m/s².
The formula to apply here is ;
Weight due to gravity=mg where m is mass of the man and g is acceleration due to gravity.
Due to additional downward acceleration the total acceleration downwards will be : 9.8+2 = 11.8 m/s²
The man weighs down on the elevator floor with a force of ;
F=m(a+g) where m is mass of man, a is acceleration
F=80( 9.8+2)
F=80(11.8)= 944 N
The reaction force by the floor of the elevator is thus 944 N
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Elevator physics :brainly.com/question/13464055
Keywords : elevator, acceleration, moving upwards, reaction force, floor
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320÷((11−9)32(11−9)32) x 8
320÷((352-288)(352-288) x 8
320÷(64 x 64) x 8
320÷4096 x 8
0.078125 x 8
0.625
Answer:0.625
Answer:
he would pay $4.50 for it.
Step-by-step explanation:
all you do is take the $30 and times that by 15% and you get $4.50.
→ Solutions
⇒ Simplify <span><span><span>4<span>(<span>2a</span>)</span></span>+<span>7<span>(<span>−<span>4b</span></span>)</span></span></span>+<span><span>3c</span><span>(5)</span></span></span><span>⇒ </span><span><span><span><span><span>8a</span>+</span>−<span>28b</span></span>+<span>15<span>c
Answer
</span></span></span></span><span>⇒ </span><span>8a−28b</span><span>+</span><span>15c</span>