Find the equation of the line
2 answers:
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We are looking to find P(X>60 students)
X is normally distributed with mean 50 and standard deviation 5
We need to find the z-score of 60 students
To find the probability of P(Z>2), we can do 1 - P(Z<2)
So we read the probability when Z<2 which is 0.9772, then subtract from one we get 0.0228
The number of students that has score more than 60 is 0.0228 x 1000 = 228 students
X is normally distributed with mean 50 and standard deviation 5
We need to find the z-score of 60 students
To find the probability of P(Z>2), we can do 1 - P(Z<2)
So we read the probability when Z<2 which is 0.9772, then subtract from one we get 0.0228
The number of students that has score more than 60 is 0.0228 x 1000 = 228 students
Answer:
(C) 220
Step-by-step explanation:
Let x represent the number of adult tickets sold and y represent the number of student tickets sold. With the information given, we can set up two equations:
(Since for every adult ticket sold, $5 is made and for every student ticket sold, $3 is made)
In the first equation, we can represent x in terms of y:
And then, we can substitute x in the second equation for 360 - y to get:
which simplifies to:
and therefore,
.
Hope this helps :)