Question

Sam entered three functions into a graphing calculator, y1 = x + 2, y2 = x2 + 2, and y3 = 2x. A portion of the table created by those functions is shown below.

Answer 1

We have the following functions:
 y1 = x + 2
 y2 = x ^ 2 + 2
 y3 = 2 ^ x

 For x = 0:
 y1 = 0 + 2 = 2
 y2 = 0 ^ 2 + 2 = 0 + 2 = 2
 y1 = y2

 For x = 5
 y2 = 5 ^ 2 + 2 = 25 + 2 = 27
 y3 = 2 ^ 5 = 32
 y3> y2

 For x = -1:
 y1 = -1 + 2 = 1
 y2 = (-1) ^ 2 + 2 = 1 + 2 = 3
 y3 = 2 ^ (- 1) = 1/2 = 0.5
 y3 <y1 <y2

 Answer:
 y1 = y2
 y3> y2
 y3 <y1 <y2