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Leni [432]
2 years ago
13

The perimeter of a rectangular playground is 494 yards. The length of the playground is 7 more than twice the width. Find the le

ngth and width.​
Mathematics
1 answer:
lbvjy [14]2 years ago
6 0

Answer:

https://youtu.be/wOH_gVtidns

I recorded a video of myself explaining it hope it helps ;)

Step-by-step explanation:

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Pls help this is due soon check 2 that apply
dem82 [27]

Answer:

I am pretty sure it is option a and c

Sorry if i am wrong

3 0
3 years ago
Find the equation of the line that is perpendicular to the x-axis and passes through the point (-10,-1). Give the full equation
Tomtit [17]

Answer:

x = -10

Step-by-step explanation:

First, determine the slope of the answer. The x-axis is a horizontal line, thus the new line must be vertical. All vertical lines are represented by the equation x = a number. That number represents the x-value of all the points the vertical line passes through.

So, since the line passes through (-10, -1), take the x-value of that point and put it into that equation. Thus, x = -10.

7 0
2 years ago
I need help asap please
olga55 [171]
8x^2y is correct
Hope this helps
8 0
3 years ago
Solve for x. 4x − 33=7
tatuchka [14]

Note the equal sign. What you do to one side, you do to the other.

Do the opposite of PEMDAS. First, add 33 to both sides

4x - 33 (+33) = 7 (+33)

4x = 40

Next, divide by 4

4x/4 = 40/4

x = 40/4

x = 10

10 is your answer

hope this helps

5 0
3 years ago
Read 2 more answers
A 50-foot ladder leans against a building. If the base of the ladder is 6 feet from the base of the building, what is the angle
adell [148]

Answer:

The angle between the building and the ladder \theta = 6.9°

Step-by-step explanation:

Given data

AB = 50 ft = length of the building

BC = 6 ft

\theta = Angle between the ladder & building

From Δ ABC

\sin \theta = \frac{BC}{AB}

\sin \theta= \frac{6}{50}

\theta = 6.9°

This is the angle between the building and the ladder.

4 0
3 years ago
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