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Gwar [14]
3 years ago
11

Mr. frankel bought 7 tickets to a puppet show and spent $24. he bought a combination of child tickets for $2 each and adult tick

ets for $4 each. which system of equations below will determine the number of adult tickets, a, and the number of child tickets, c, he bought
Mathematics
1 answer:
nydimaria [60]3 years ago
6 0
Let x be the number of child tickets he bought
Let y be the number of adult tickers he bought

① x+y=7 (child tickets+adult ticket=7 tickets in total)
② 2x+4y=24 (price of child tickets+price of adult tickets=$24 in total)

We may simply the second equation since all of the coefficients are divisible by 2.

① x+y=7
② x+2y=12

We can now use elimination by multiplying the second equation by -1.

② -(x+2y=12)
② -x-2y=-12

① x+y=7
② -x-2y=-12

Now putting the equations together,
-y=-5
y=5
x=2

Therefore he bought 2 child tickets and 5 adult tickets
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Answer:

h=h= \frac{5R^{3} }{LU}

Step-by-step explanation:

1.) You must isolate the h from the equation by dividing both sides by L (or multiply by its reciprocal, which in this case, the reciprocal on L is \frac{1}{L}    .....So it would look like:

(\frac{1}{L} )*\frac{5R^{3} }{U} = \frac{L}{h}* (\frac{1}{h} )\\

2.) Simplify the equation if you need to (in this case, its not needed)

\frac{5R^3}{LU} =h

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3 years ago
If U = { 1 , 2 , 3 , 4 , 5 ,6 , 7 , 8 , 9 }. A={1 , 2 , 3 , 4 } , B= {2 , 4 , 6 , 8 } .Find
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Answer:

(A - B)' = {2, 4, 5, 6, 7, 8, 9}

(A n B) = {2, 4}

Step-by-step explanation:

Given the set :

U = { 1 , 2 , 3 , 4 , 5 ,6 , 7 , 8 , 9 }

A={1 , 2 , 3 , 4 } , B= {2 , 4 , 6 , 8 }

(A - B) = elements of A which are not in B

(A - B) = {1, 3}

(A - B)' = the complement of A - B ; element in the universal set which are not in A - B

(A - B)' = {2, 4, 5, 6, 7, 8, 9}

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(A n B) = {2, 4}

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