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DiKsa [7]
3 years ago
8

Solve each problem. If you get stuck, consider using the double number lines. During a basketball practice, Mai attempted 40 fre

e throws and was successful on 25% of them. How many successful free throws did she make? A double number line with 7 evenly spaced tick marks. The top number line is labeled “free throws” and the first tick mark is labeled 0. The other tick marks are unlabeled. The bottom number line is not labeled and starting with the first tick mark 0, 25 percent, 50 percent, 75 percent, 100 percent, 125 percent, and 150 percent are labeled. Yesterday, Priya successfully made 12 free throws. Today, she made 150% as many. How many successful free throws did Priya make today?

Mathematics
2 answers:
expeople1 [14]3 years ago
7 0

Answer: 10, I think...

Elena-2011 [213]3 years ago
4 0
Answer is ten ✨ good work there u go mark me brainliest
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matrenka [14]

Answer:

La densidad del líquido desconocido es de aproximadamente 0,6855 g/ml.

Step-by-step explanation:

Los parámetros dados son;

La masa del recipiente vacío = 38,52 g

La masa total del recipiente cuando está lleno de agua = 137,26 g

La masa total del recipiente cuando se llena con el líquido desconocido = 106.21 g

Por lo tanto;

La masa del agua = La masa total del recipiente cuando está lleno de agua - La masa del recipiente vacío

La masa del agua = 137,26 g - 38,52 g = 98,74 g

La masa del líquido desconocido = 106,21 g - 38,52 g = 67,69 g

La gravedad específica del líquido desconocido = (La densidad de la sustancia desconocida) / (La densidad del agua)

De lo que tenemos;

La gravedad específica del líquido desconocido = (La masa del líquido desconocido) / (La masa de un volumen igual de agua)

∴ La gravedad específica del líquido desconocido = (67,69 g) / (98,74 g) ≈ 0,6855

De la ecuación, gravedad específica = (La densidad del líquido desconocido) / (La densidad del agua) y la densidad del agua = 1 g / ml, tenemos;

gravedad específica ≈ 0.6855 = (La densidad del líquido desconocido) / (1 g / ml)

La densidad del líquido desconocido ≈ 0.6855 × 1 g / ml ≈ 0.6855 g / ml

La densidad del líquido desconocido ≈ 0,6855 g / ml.

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Step-by-step explanation:

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Carl is boarding a plane. He has 2 checked bags of equal weight and a backpack that weight 4kg. The total weight of Carl’s bagga
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35 = 4 + 2b

2b = 35 - 4

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35 - 4 = 31

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Divide by 2

15.5 = b

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